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3 years ago

Write the first ten terms of a sequence whose first term is -10 and whose common difference is -2.

Mathematics

2 answers:

Ilya [14]3 years ago

6 0

-10, -12, -14, -16, -18, -20, -22, -24, -26,-28.
Hope this helps :)

AURORKA [14]3 years ago

4 0

Answer:

see explanation

Step-by-step explanation:

Given that the first term is - 10 and the common difference between consecutive terms is - 2, then

To obtain the next term from the previous term subtract 2 from it

- 10 - 2 = - 12, - 12 - 2 = - 14, - 14 - 2 = - 16, - 16 - 2 = - 18 and so on

The first 10 terms are

- 10, - 12, - 14, - 16, - 18, - 20, - 22, - 24, - 26, - 28

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<h3>How to prove that QRST is a parallelogram?</h3>

The coordinates are given as:

Q = (-1,-1)

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S = (-4,5)

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Calculate the length of each side using:

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$TQ = \sqrt{(-7 + 1)^2 + (-5 + 1)^2} = \sqrt{52}$

The above computations show that opposite sides are equal.

Next, we determine the slope of each side using:

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The above computations show that opposite sides are parallel, because they have equal slope

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Read more about parallelograms at:

brainly.com/question/3050890

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