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Vlada [557]
2 years ago
5

Write the first ten terms of a sequence whose first term is -10 and whose common difference is -2.

Mathematics
2 answers:
Ilya [14]2 years ago
6 0
-10, -12, -14, -16, -18, -20, -22, -24, -26,-28.
Hope this helps :)
AURORKA [14]2 years ago
4 0

Answer:

see explanation

Step-by-step explanation:

Given that the first term is - 10 and the common difference between consecutive terms is - 2, then

To obtain the next term from the previous term subtract 2 from it

- 10 - 2 = - 12, - 12 - 2 = - 14, - 14 - 2 = - 16, - 16 - 2 = - 18 and so on

The first 10 terms are

- 10, - 12, - 14, - 16, - 18, - 20, - 22, - 24, - 26, - 28

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o-na [289]

Answer:

\sqrt{2} a

Step-by-step explanation:

The distance between point (x1,y1) and (x2,y2) on a coordinate plane is given by expression \sqrt{(x1-x2)^2+(y1-y2)^2}

In the problem given coordinate points are

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Thus, distance between these points are given by

distance = \sqrt{(x1-x2)^2+(y1-y2)^2}\\=>distance = \sqrt{(0-a)^2+(a-0)^2}\\=>distance = \sqrt{(a)^2+(a)^2}\\\\=>distance = \sqrt{2a^2}\\=>distance = \sqrt{2} a

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