I’m 98% sure that it is B because customer service would be provided to people who buy from the company and need help
// Variable to keep track of array size
int length = 0;
// Array itself
int array[] = {};
// while loop will take input in the array until a negative number is entered
while(input>=0){
stdin = new Scanner(System.in);
array[length] = stdin;
length +=1;
}
// int variable to terminate while loop
int i =0;
// keep track of index of output array
int y =0;
while(arr[i] != length){
// making output array
int output[]={}; bool flag;
// put the element in out put array considering if it the desired one
output[y] = array [i];
// Now check if it was the desired?
for(int z=1;z<=length;z++){
if(array[i+z]!=output[y]){
flag = true;
}
else
{
output[y]=0;
y+=1;
}
if(array[i+z+1]=output[y] && flag == true){
output[y] = array[i];
y+=1;
}
}
//output the array
for(int o=0;o<y;o++)
System.out.println(output[o];
This is true, you can also advance by hitting enter/return.
Answer:
Configure the CloudFront CDN and the use of S3 bucket as the origin
Explanation:
The S3 backed site receives more than 400 reader queries every second regularly and is increasing gradually. Customize the CloudFront CDN and then use the S3 bucket as the source to obtain the highest efficiency as web traffic continued to increase.
So, that's why the following answer is correct according to the given scenario.