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Murrr4er [49]
3 years ago
7

Atmospheric pressure at Earth's surface is approximately 14.7 pounds per square inch. Atmospheric pressure decreases by approxim

ately 16% for each mile increase in height above the surface. Write an exponential equation for the atmospheric pressure P (in pounds per square inch) x miles above Earth's surface. At what height (in miles) is the atmospheric pressure 11 pounds per square inch? Round to the nearest tenth.
Mathematics
1 answer:
chubhunter [2.5K]3 years ago
3 0

Answer:

The standard, or near-average, atmospheric pressure at sea level on the Earth is 1013.25 millibars, or about 14.7 pounds per square inch.

The gauge pressure in my automobile tires is a little more than twice that value. If you live at a higher altitude, the pressure will be lower since there is less air above weighing down upon you. The pressure also varies by relatively small amounts as high and low pressure systems move past.

Step-by-step explanation:

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Artyom0805 [142]

Step-by-step explanation:

V=1/3 × πr²h

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V= π×(4)²×(6)/3

V=96π/3

V=32π

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8 0
3 years ago
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How would I simplify and solve for X in this trigonometric equation? (Radians)
Phoenix [80]

Answer:

Please, refer to the images below

Step-by-step explanation:

We need to solve for x in the equation

cos (x+ pi) ^2 = sin (x)

cos (x+ pi) = - cos(x)

(-cos (x)) * (-cos (x)) = sin(x)

cos(x) ^2 = sin(x)

We know that

cos(x) ^2  + sin(x) ^2  = 1

cos(x) ^2 = 1 - sin(x) ^2

1 - sin(x) ^2 = sin(x)

sin(x) ^2 + sin (x) -1 = 0

Let A = sin(x)

A^2 + A - 1 = 0

(solutions attached in picture 1)

This means that

x = arcsin(A)

(solutions attached in picture 2)

8 0
3 years ago
Jake recorded a special album in honor of Mothers Day. His mom was so excited she purchased 40% of the copies in true store. She
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The answer is 200.

40% = 80

40%/4 = 80/4

10% = 20

10% • 10 = 20 • 10

100% = 200

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4 0
3 years ago
I need help with these
3241004551 [841]

1. a= 60 (vertically opposite angles)

b= 360-(60+60)=240/2= 120 (angles at a point)

c= 120 (vertically opposite angles with b)

2. c= 90-40= 50 (vertically opposite angles)

b=a=360-90-90=180/2=90 (angles at a point)

3. a= 180-52-51= 77 (angles on a straight line)

b=52 (angles at a point)

d=51 (angles at a point)

c=77 (angles at a point)

4. a= 60 (vertically opposite angles)

b= 360-(60+60)=240/2= 120 (angles at a point)

c= 120 (vertically opposite angles with b)

e=65

d=f= 360-65-65=230/2=115

h=55

i=g=360-55-55=250/2=125

5. b=163

a=90

e=70

d=360-70-70=220/2=110

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4 0
3 years ago
Which irrational number can be multiplied by negative square root of 41 to get a product that equals 1?
melomori [17]

For this case we define the following variable:

<em>x: unknown number </em>

We then have the following equation:

- \sqrt {41} x = 1

From here, we clear the value of x.

We have then:

x = - \frac {1} {\sqrt {41}}

Answer:

An irrational number that can be multiplied by negative square root of 41 to get a product that equals 1 is:

x = - \frac {1} {\sqrt {41}}


7 0
4 years ago
Read 2 more answers
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