Answer:
The first digit of the quotient should be placed at the leftmost place of the places of the all the digits in the quotient.This is so from the basic rule of division.
Step-by-step explanation:
The quotient is given by,
![[\frac {4,839}{15}]](https://tex.z-dn.net/?f=%5B%5Cfrac%20%7B4%2C839%7D%7B15%7D%5D)
[where [x] is the greatest integer function on x]
= [322.6]
= 322
and the remainder is given by,
= 9
So, the first digit of the quotient should be placed at the leftmost place of the places of the all the digits in the quotient and this is so from the very basic rule of division.
Answer:
Please see the attached picture ! :D
-------- HappY LearninG <3 ----------
Set the whole expression = to 0 and solve for x.
3x^(5/3) - 4x^(7/3) = 0. Factor out x^(5/3): x^(5/3) [3 - 4x^(2/3)] = 0
Then either x^(5/3) = 0, or 3 - 4x^(2/3) = 0.
In the latter case, 4x^(2/3) = 3.
To solve this: mult. both sides by x^(-2/3). Then we have
4x^(2/3)x^(-2/3) = 3x^(-2/3), or 4 = 3x^(-2/3). It'd be easier to work with this if we rewrote it as
4 3
--- = --------------------
1 x^(+2/3)
Then
4
--- = x^(-2/3). Then, x^(2/3) = (3/4), and x = (3/4)^(3/2). According to my 3 calculator, that comes out to x = 0.65 (approx.)
Check this result! subst. 0.65 for x in the given equation. Is the equation then true?
My method here was a bit roundabout, and longer than it should have been. Can you think of a more elegant (and shorter) solution?
B i hope it helps if not sorry
12 +4m = 24
4m = 12
m = 12/4
m = 3 so choice C. is right sure
