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sleet_krkn [62]
3 years ago
9

The length of a rectangle is 1 more yd than twice the width, and the area of the rectangle is 66 yd squared. Find the dimensions

of the rectangle.
Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
6 0

Width = 5.5yd  

Length = 12yd

<u>Explanation:</u>

Area of rectangle =  66yd^{2}

Let width of the rectangle = b ,  

So, length = 2b+1  

Area of rectangle = (length X width) - eqn 1

Putting the value of length and width in above equation 1,

66yd^{2} = (2b+1) X b\\66yd^{2} = 2b^{2} + b\\2b^{2} +b-66 = 0\\

On solving the equation we get,

b = 5.5yd

So, width (b) = 5.5yd

and length = 2(5.5) + 1

l = 12yd

Hence,  

Width = 5.5yd  

Length = 12yd

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