Question

The length of a rectangle is 1 more yd than twice the width, and the area of the rectangle is 66 yd squared. Find the dimensions of the rectangle.

Answer 1

Width = 5.5yd  

Length = 12yd

Explanation:

Area of rectangle =  $66yd^{2}$

Let width of the rectangle = b ,  

So, length = 2b+1  

Area of rectangle = (length X width) - eqn 1

Putting the value of length and width in above equation 1,

$66yd^{2} = (2b+1) X b\\66yd^{2} = 2b^{2} + b\\2b^{2} +b-66 = 0$

On solving the equation we get,

b = 5.5yd

So, width (b) = 5.5yd

and length = 2(5.5) + 1

l = 12yd

Hence,  

Width = 5.5yd  

Length = 12yd