Answer:
a = $31.23 per month
b = $20.83 per month
c = 249.98 = $249.98 interest charges
= $624-249.98 = 374.02 profit part decrease 8% inc.
d = 35.35%
e = Answer is in the name; basic payment is a contract which means whilst account remains open charges are requested without fail. Should balance be less or on zero, charges are still applied.
Step-by-step explanation:
2500 x 1.2499 = interest only for start month 13 =3124.75
3124.75/ 100 x 1.08 = 8% of this = 249.98 each year.
We only have to divide each by 12 to work out monthly individual charges and subtract to find out payments.
3124.75 - 249.98 = 2874.77 = Total after charges each year.
249.98/12 = 20.83 = monthly charges.
3124.75- 2500 = 624.75 payments each year
624.75/12 = 52.06 month 1 payment before charge
52.06-20.83 =31.23 total minimum payment
2500 + 249.98
Percentage = 200:600 = 1/3 33% + (comparing to ratio 10:25 closer to 40%)
We find ratio 200:600= 33.33 + 49.995/24.75 = 2.02
33+2.02 = 35.35%
Answer:
The function for the outside temperature is represented by ![T(t) = 85\º + 15\º \cdot \sin \left[\frac{t-6\,h}{24\,h} \right]](https://tex.z-dn.net/?f=T%28t%29%20%3D%2085%5C%C2%BA%20%2B%2015%5C%C2%BA%20%5Ccdot%20%5Csin%20%5Cleft%5B%5Cfrac%7Bt-6%5C%2Ch%7D%7B24%5C%2Ch%7D%20%5Cright%5D)
, where t is measured in hours.
Step-by-step explanation:
Since outside temperature can be modelled as a sinusoidal function, the period is of 24 hours and amplitude of temperature and average temperature are, respectively:
Amplitude
Mean temperature
Given that average temperature occurs six hours after the lowest temperature is registered. The temperature function is expressed as:
![T(t) = \bar T + A \cdot \sin \left[2\pi\cdot\frac{t-6\,h}{\tau} \right]](https://tex.z-dn.net/?f=T%28t%29%20%3D%20%5Cbar%20T%20%2B%20A%20%5Ccdot%20%5Csin%20%5Cleft%5B2%5Cpi%5Ccdot%5Cfrac%7Bt-6%5C%2Ch%7D%7B%5Ctau%7D%20%5Cright%5D)
Where:
- Mean temperature, measured in degrees.
- Amplitude, measured in degrees.
- Daily period, measured in hours.
- Time, measured in hours. (where t = 0 corresponds with 5 AM).
If , and 
, the resulting function for the outside temperature is:
We know A=L•W so set 43 equal to A. Equation should look like this thus far: 43=L•W. Now when the question says more than we know that means adding. Since we don’t know the width let w=width. So know your equation should look like this: 43=2+w•(w). Knowing this equation you should be able to solve for the dimensions of the sign. If you need help on that let me know.
Answer: 0.17584
Step-by-step explanation:
3.14*0.056=
3.14*0.05+3.14*0.006=
0.157+0.01884=0.17584
