Answer:
-2
Step-by-step explanation:
The integer of - 2 is - 2 only as integers can be positive and negative whole numbers
The answer is infinitely many solutions.
If you graph them both are a straight line which means they are infinite
Answer:
Class Boundary = 1 between the sixth and seventh classes.
Step-by-step explanation:
Lengths (mm) Frequency
1. 140 - 143 1
2. 144 - 147 16
3. 148 - 151 71
4. 152 - 155 108
5. 156 - 159 83
6. 160 - 163 18
7. 164 - 167 3
The class boundary between two classes is the numerical value between the starting value of the higher class, which is 164 for the 7th class in this case, and the ending value of the class of the lower class, which is 163 for the 6th class in this case.
Therefore the class boundary between the sixth and seventh classes
= 164 - 163 = 1
Therefore Class Boundary = 1.
It can be seen that class boundary for the frequency distribution is 1.
If we take the difference between the lower limits of one class and the lower limit of the next class then we will get the class width value.
Therefore, Class width,
w = lower limit of second class - lower limit of first class
= 144 - 140
= 4
The required expression would be
Step-by-step explanation:
Since we have given that
subtract 4 times the positive square root of z from thrice of x
So, thrice of x would be
4 times the positive square root of z would be
Subtract the later from former would be
Hence, the required expression would be
# learn more:
13 subtracted from thrice of a number.
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