Answer:
Step-by-step explanation:
perimeter of a rectangle = twice the length plus twice the width
P = 2L + 2W equation 1 P = 86 ft
Given the length is seven feet more than the width
L = W + 7 equation 2
Substitute equation 2 into equation 1
P = 2(W+7) + 2W = 86 ft
2W +14 + 2W = 86 ft
4W = 86 - 14
W = 72 / 4
W = 18 feet
The sum of two numbers:
x + y = 108
The difference of the same two numbers:
x - y = 78
We can use substitution to figure out x and y:
x - y = 78 can be changed to x = 78 + y
We can plug this into the first equation:
78 + y + y = 108
78 + 2y = 108
2y = 30
y = 15
Now solve for x using any of the two equations. I'll use the first equation since it's easier:
x + 15 = 108
x = 93
The slope of the function for pronghorn antelope is 60.78 which infers that the rate of speed of the pronghorn is 60.78 miles per hour.
7) The given function that represents the speed of the pronghorn is
y = 60.78x - 5.4
Comparing this function with the general equation of a straight line
y = mx + c we can conclude that the slope of the function is 60.78 .
So the Pronghorn's rate of speed is 60.78 miles per hour.
8) Now the speed of the cheetah is given in the form of a table.
Let us take any two points on the graph
(0.5,21.85) and (2,118.60)
Slope of the line passing through these two points
= (118.6-21.85)/(2-0.5)
=64.5
So the slope of the graph is 64.5 and the average rate of speed of the Cheetah is 64.5 miles per hour.
9) From the above two slopes and the rate of speed we can conclude that the speed of the cheetah is 64.5 mph which is greater than that of the pronghorn 's speed of 60.78 miles per hour.
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Extraneous solutions are the values that we get when solving equations which aren't really solutions to the equation.
<h3>
What are extraneous solutions?</h3>
Your information is incomplete. Therefore, an overview will be given. An extraneous solution is the root of a transformed equation which is not a root of the original equation since it was excluded from the domain of the original equation.
The reason extraneous solutions exist is simply that some operations produce extra answers, and these operations are a part of the path to solving the problem.
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