All categories

2 years ago

If 12-3n = -7n-4(n +5), what is 32-5n

Mathematics

1 answer:

Yuliya22 [10]2 years ago

7 0

Answer:

Step-by-step explanation:

12-3n=-7n-4(n+5)

Step 1: distribute

12-3n=-7n-4n-20

Step 2: Combine like terms

12-3n=-11n-20

Step 3: Move N to one side

12-3n=-11n-20

+11n +11n

12+8n=-20

Step 4: Get normal numbers to the other side

12+8n=-20

-12 -12

8n=-32

Step 5: Take away the number infront of N by dividing each side by the number of Ns

8n=-32

/8 /8

n= -4

Step 6: Plug N into: 32-5n

32-5(-4)

Step 7: Get rid of parenthesis by multiplying. Negative times Negative is positive.

32+20

Step 8: Finish the problem

Answer is 52

You might be interested in

Prove De Morgan's law by showing that each side is a subset of the other side by considering x ∈ A⎯⎯⎯ A ¯ ∩ B⎯⎯⎯ B ¯ .

adelina 88 [10]

Solution :

We have to prove that $\overline{A \cup B} = \overline{A} \cap \overline{B}$ (De-Morgan's law)

Let $x \in \bar{A} \cap \bar{B},$ then $x \in \bar{A}$ and $x \in \bar{B}$

and so $x \notin \bar{A}$ and $x \notin \bar{B}$ .

Thus, $x \notin A \cup B$ and so $x \in \overline{A \cup B}$

Hence, $\bar{A} \cap \bar{B} \subset \overline{A \cup B}$ .........(1)

Now we will show that $\overline{A \cup B} \subset \overline{A} \cap \overline{B}$

Let $x \in \overline{A \cup B}$ ⇒ $x \notin A \cup B$

Thus x is present neither in the set A nor in the set B, so by definition of the union of the sets, by definition of the complement.

$x \in \overline{A}$ and $x \in \overline{B}$

Therefore, $x \in \overline{A} \cap \overline{B}$ and we have $\overline{A \cup B} \subset \overline{A} \cap \overline{B}$ .............(2)

From (1) and (2),

$\overline{A \cup B} = \overline{A} \cap \overline{B}$

Hence proved.

3 0

2 years ago

Christina can paint a chair in

Maurinko [17]

Answer:

2

Step-by-step explanation:

I think because I had the same kind of question and the answer was 2 ,

hopefully it helps u☺️

6 0

3 years ago

Please help I’m failing math

jasenka [17]

Answer:

3x+3

Step-by-step explanation:

8 0

2 years ago

What is the solution to 1/3(s-2)=s+4

raketka [301]

$\frac{1}{3} * (s-2)=s+4 \\ \\ \frac{s-2}{3}=s+4 \\ \\ s-2=3(s+4) \\ \\ s-2= 3s+12 \\ \\ s-3s=12+2 \\ \\ -2s= 14 \\ \\ \boxed{s= -\frac{14}{2}=-7}}$

8 0

3 years ago

Slope m = -2 and y -intercept b = -1

algol [13]

Y = -2m -1 is your equation

3 0

3 years ago

Read 2 more answers