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user100 [1]
3 years ago
10

Is 3/5 equivalent to 6/8

Mathematics
2 answers:
Nastasia [14]3 years ago
5 0
No, bc 3/5 is 3/5. 6/8 reduced is 3/4. So no
slava [35]3 years ago
5 0
No because 3/5 = 60% and 6/8 = 75%
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Ibuki factored 12x^7as (4x^3)(3x^4)
Marina86 [1]

Answer:

Both are correct.

Step-by-step explanation:

The key understanding here is that you can factor a monomial in many different ways!

To check if any of the factorizations is correct, we can multiply the factors and see if their product is really 12x^712x

7

12, x, start superscript, 7, end superscript.

Hint #22 / 4

\begin{aligned} (\blueD{4}\maroonD{x^3})(\blueD{3}\maroonD{x^4})&=(\blueD{4})(\blueD{3})(\maroonD{x^3})(\maroonD{x^4}) \\\\ &=\blueD{12}\maroonD{x^7} \end{aligned}

(4x

3

)(3x

4

)

​

 

=(4)(3)(x

3

)(x

4

)

=12x

7

​

So Ibuki is correct!

Hint #33 / 4

\begin{aligned} (\blueD{2}\maroonD{x^6})(\blueD{6}\maroonD{x})&=(\blueD{2})(\blueD{6})(\maroonD{x^6})(\maroonD{x}) \\\\ &=\blueD{12}\maroonD{x^7} \end{aligned}

(2x

6

)(6x)

​

 

=(2)(6)(x

6

)(x)

=12x

7

​

So Melodie is also correct!

Both Ibuki and Melodie are correct.

8 0
3 years ago
"Which shapes are topologically equivalent to Choice 2?
DanielleElmas [232]
<span>Which shapes are topologically equivalent to Choice 2?  D. NONE

Choice 1, 3, and 4 are topologically equivalent. These figures each have two holes. 

Choice 2 has three holes and is different from the other. 

Topologically equivalent figures are figures that can be rearranged to form another shape without breaking.</span>
8 0
3 years ago
Yoki is running a 10-mile race. She runs at a steady speed and then slows down, stops to get a drink of water, and
kondor19780726 [428]
Do you have any pictures to choose from anything to show what im looking at?
4 0
3 years ago
Read 2 more answers
Mia spent 30 minutes answering the math questions on the exam. This was Three-fifths of the total amount of time allotted for th
soldier1979 [14.2K]

Answer:

x×3/5=30

3x/5=30

3x=5×30

3x=150

x=150/3

x=50

4 0
2 years ago
Find the zeroes of the polynomial function f(x)=x^4-5x^3+11x^2-25x+30.
katen-ka-za [31]

Step-by-step explanation:

x⁴ − 5x³ + 11x² − 25x + 30

x⁴ − 5x³ + 6x² + 5x² − 25x + 30

x² (x² − 5x + 6) + 5 (x² − 5x + 6)

(x² + 5) (x² − 5x + 6)

(x² + 5) (x − 2) (x −3)

The zeros are 2, 3, and ±√5i.

7 0
3 years ago
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