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3 years ago

Which table is a probability distribution table?

Mathematics

1 answer:

FrozenT [24]3 years ago

4 0

Step-by-step explanation:

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See if you can Answer 9x^2+12x-24

Goshia [24]

The only solution would be to factor the equation which would be 3(3x^2+4x-8)

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4 years ago

Please help with these algebra questions

Lana71 [14]

Answer:

1. x= -b/a

2. x=b/a+c

3. x=b/a

4. x=a/-b+c

5. x= -a/b

6. x=c/a+b

7. x= -c/a+b

8. x=c/a-b

9. x=-b/c

10. x=a/b+c

11. x=c/-a+b

12. x= -c/b

13. x=a/-b+c

14. x= -c/a+b

15. x= -a/b+c

16. x=-a/-b+c

17. x= c/a+b

18. x= -c/a-b

19. x= -b/a+c

20. x=b/a+c

Step-by-step explanation:

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4 years ago

One angle of an isosceles triangle measures 96 degrees. Which other angles could be in that isosceles triangle?

Fofino [41]

One angle of an isosceles triangle measures 96 degrees. Which other angles could be in that isosceles triangle?

Ans is 42
But not sure about it

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3 years ago

Solving systems of equations using substitution -4x-y=16 Y=-8

Goshia [24]

ᑕᒪIᑕK Oᑎ ᑭIᑕ ᖴOᖇ ᑭᖇOOᖴ

᙭= -2

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3 years ago

Which of the following inequalities represents all values of X for which the quotient below is defined?

Tomtit [17]

Answer:

$x \ge 1$

Step-by-step explanation:

Given

$\sqrt{6(x - 1)} \div \sqrt{3x^2$

Required

x for $which$ the function is $de fi ned$

To do this, we set the numerator root $\ge 0$

So, we have:

$6(x - 1) \ge 0$

Divide by 6

$(x - 1) \ge 0$

Solve for x

$x \ge 1$

Also, we set the denominator greater than 0:

$3x^2 > 0$

Divide by 3

$x^2 > 0$

Take square roots

$x > 0$

So, we have:

$x > 0$ and $x \ge 1$

Combine both to give:

$x \ge 1$

6 0

3 years ago