The graph of <span>y=-0.5 sqrt (x-3)+2
Df= {x/x-3>=0}
Df= [3, + infinity[
derivative of f(x)
f'(x)= -0.5 x 2 /</span>sqrt (x-3)= - 1/sqrt (x-3) <0, f is a decreasing function for all x in the Df
limf(x)=2 x--------->3, limf(x)=-infinity, x--------->+infinity
look at the graph
When the base of a triangle is fixed at 2.218 millimeters, the area will be 0.1098 mm².
<h3>What will the area be?</h3>
It should be noted that the area of a triangle is calculated as:
Area of triangle = (1/2)×base×height
= (1/2) × 2.218 mm × 0.099 mm
= 1.109 mm × 0.099 mm
= 0.109791 mm²
≈ 0.1098 mm²
Therefore, the <em>area</em> is 0.1098 mm².
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The base of a triangle is fixed at 2.218 millimeters. Determine the number of
significant figures of the area of the triangle with each given height of 0.099mm.
Answer:
The fraction of one pound of cheese to be used in each sandwich is 1/8
Step-by-step explanation:
Here, we have a question that requires the method of dealing with the division of fractions.
To divide a fraction by a whole number, we multiply the denominator of the fraction by the whole number as follows;
Quantity of cheese Shane has = 1/2 pound
Number of sandwiches to be made = 4
Amount of cheese per sandwich = 1/2÷4 = 1/8.
Answer: ゼロ
Step-by-step explanation:
Answer:
7/23
Step-by-step explanation:
