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Novosadov [1.4K]
3 years ago
7

How many different four-digit numbers can be formed with the numbers 7; 4; 5; 1; 2; 9; and 8?

Mathematics
1 answer:
vodomira [7]3 years ago
8 0
Two answers are possible.
One is with the repetition of digits.
The other is without repetition of digits.
ANSWER 1: With Repetition
Numbers: 1,2,4,5,7,8
There are 4 digits __ __ __ __
1st digit can be filled by any of the 6 numbers.
Similarly 2nd, 3rd and 4th digits.
Hence each digit will have 6 possibilities.
Therefore no.of 4 digit numbers that can be formed are 6 x 6 x 6 x 6 = 1296
ANSWER 2: Without Repetition
4 digits __ __ __ __
Now the first digit can be filled by any of the six numbers. Therefore there are 6 possibilities
The second digit will have only 5 possibilities as one of the numbers gets used up by the 1st digit.
Similarly the 3rd and 4th digits will have 4 and 3 possibilities respectively.
Therefore no.of 4 digit numbers that can be formed are 6 x 5 x 4 x 3 = 360
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A student earned grades of​ B, B,​ A, C, and D. Those courses had these corresponding numbers of credit​ hours: 4,​ 5, 1,​ 5, 4.
antiseptic1488 [7]

Answer:

<h2> 1.69</h2>

Step-by-step explanation:

Let the five courses with their corresponding credit hours be represented as shown;

FST 201 = 4

FST 203 = 5

FST 112 = 1

FST 219 = 5

FST 223 = 4

If a student earned grades of​ B, B,​ A, C, and D respectively in those courses with the following grading system  A =​4, B =​3, C =​2, D =​1, and F =0, before we can get the student GPA, we need to know the total credit point for the five courses.

Credit point for each course = Number of credit hour * point for each grade

FST 201 = 4 * 4 = 16points (A)

FST 203 = 5 * 4 = 20points (A)

FST 112 = 1 * 4  = 4points (A)

FST 219 = 5 * 4 = 20points (A)

FST 223 = 4 * 4 = 16points (A)

Total credit point = 16+20+4+20+16 = 76points

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Total credit point gotten by the student = 45points.

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