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tensa zangetsu [6.8K]
2 years ago
6

Can someone help me please?:)

Mathematics
1 answer:
Effectus [21]2 years ago
7 0

Answer:

can you send it clearly it is blur see

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what is 0 + 0? I NEED HELP PLS RN RN IM GETTING GRADED ON THIS PLS HELP WILL MARK BRAINLIEST PLS HELP
kicyunya [14]

It's 00000000000000000000000

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About how many more website hits were there on Saturday than on Friday?
Ainat [17]

Answer:

1,000 hits

Step-by-step explanation:

Saturday: 2,000 hits

Friday: 1,000 hits

2,000 - 1,000 = 1,000

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Factorise x squared + 4x + 3 ​
olganol [36]
<h3>Answer:  (x+1)(x+3)</h3>

===================================================

Explanation:

Let's assume it factors into (x+a)(x+b)

The goal is to find the two numbers a and b.

FOIL out (x+a)(x+b) to get x^2+(a+b)x+ab

Note how a+b is the middle term and ab is the last term.

In the original expression, 4 is the middle term and 3 is the last term.

So we need to find two numbers that

  • add to 4
  • multiply to 3

There are two ways to multiply to 3 and they are

  • 1 times 3 = 3
  • -1 times -3 = -3

But only the first way has the factors add to 4. So that means a = 1 and b = 3.

Therefore (x+a)(x+b) = (x+1)(x+3)

And x^2+4x+3 = (x+1)(x+3)

8 0
3 years ago
Paige wants to sew lace around a round table cloth. The table cloth has a diameter of 6ft. About how much lace will Paige need?
Free_Kalibri [48]
It is B because u need enough for it to do it right
5 0
3 years ago
Suppose a random sample of 50 college students are asked to measure the length of their right foot in centimeters. A 95% confide
hichkok12 [17]

Answer:

A  99% confidence interval  will be wider than a 95% confidence interval

Step-by-step explanation:

From the question we are told that

  The  95% confidence interval for for the mean foot length for students at the college is found to be 21.709 to 25.091 cm

Generally the width of a confidence interval is dependent on the margin of error.

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }

From the above equation we see that

          E \ \  \alpha \ \   Z_{\frac{\alpha }{2} }

Here  Z_{\frac{\alpha }{2} }  is the critical value of the half of the level of significance and this value  increase as the confidence level increase

Now if a  99% confidence level is  used , it then means that the value of  

 Z_{\frac{\alpha }{2} }  will increase, this in turn will increase  the margin of error and in turn this will increase the width of the confidence interval

Hence a 99% confidence interval  will be wider than a 95% confidence interval

5 0
3 years ago
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