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Oxana [17]
3 years ago
9

Please answer I need help to pass

Mathematics
1 answer:
Goryan [66]3 years ago
5 0

Answer:

the answer is A

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Question 11 (2.5 points)
Rama09 [41]

Answer:

D

Step-by-step explanation:

The answer is d, because a represents adults, and c represent children. It's $45 per adult, so $45a, and $30 per child, so $30c. a+c is equal to 10, because that's how many tickets were purchased. $45a+$30c=345, because $345 is the total amount spent on tickets.

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3 years ago
The Jennings family paid $371.40 for the year for their cable service. If their payments were the same each month, how much was
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$30.95

Step-by-step explanation:

There are 12 months in a year. $371.40 divided by 12 gives us $30.95.

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3 years ago
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What is the greatest factor of -2x?
Sveta_85 [38]

Answer:

this is prime

Step-by-step explanation:

3 0
3 years ago
A survey asks, "If the husband in a family wants children, but the wife decides that she does not want any children, is it all r
vodka [1.7K]

Answer:

a. The 99% confidence interval for the population proportion is (0.7872, 0.8610).

D. Yes, we can conclude that the population proportion exceeds 75% because 75% is below the lowest believable value of the confidence interval.

b. The 99% confidence interval would be wider than a 95% confidence interval.

As the confidence level increases, the width interval increases, as we are requiring more confidence with the same information (there is no new sample). This means that, to be more confident, the only way is to include more values in the interval.

Step-by-step explanation:

We have to calculate a 99% confidence interval for the proportion.

The sample proportion is p=0.8241.

p=X/n=581/705=0.8241

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.8241*0.1759}{705}}\\\\\\ \sigma_p=\sqrt{0.000206}=0.0143

The critical z-value for a 99% confidence interval is z=2.5758.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_p=2.5758 \cdot 0.0143=0.0369

Then, the lower and upper bounds of the confidence interval are:

LL=p-z \cdot \sigma_p = 0.8241-0.0369=0.7872\\\\UL=p+z \cdot \sigma_p = 0.8241+0.0369=0.8610

The 99% confidence interval for the population proportion is (0.7872, 0.8610).

We can conclude that there is, at least, 99% chances that the true proportion is higher than 0.7872. So there is at least 99% chances that the population proportion is higher than 0.75.

4 0
3 years ago
Solve for 4(3+x) = 8​
azamat

Answer:

x=-1

Step-by-sx=-1tep explanation:

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