The congruence statement and the rule used is: ΔTIG ≅ ΔAIN by SAS.
<h3>The Side-Angle-Side Congruence Theorem</h3>
- It is also referred to as the SAS Congruence Theorem.
- SAS Congruence Theorem is used to show that two triangles, with two pairs of congruent sides and a pair of congruent included angles, are congruent.
Thus, in the image shown below, ΔTIG and ΔAIN have:
two pairs of congruent sides - TI ≅ NI and GI ≅ AI.
one pair of congruent included angles - ∠TIG ≅ ∠AIN
Therefore, the congruence statement and the rule used is: ΔTIG ≅ ΔAIN by SAS.
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How can you visit the sun without burning up worksheet answer key is a heading for a worksheet that involves mathematical questions to calculate. The attached file displays those mathematical questions.
Before that, the sun is known as a star that is located in the middle of the Solar system. It is a virtually flawless sphere of hot plasma that has been heated by nuclear fusion processes in its center, thereby radiating energy as infrared radiation and ultraviolet light.
It is nearly impossible to visit the sun due to the degree of its temperature and radiation.
- From the image attached below which depicts the heading to the question, we have:
a) 5(x - 9) = 2x + 15
Open brackets
5x - 45 = 2x + 15
Collect like terms
5x - 2x = 45 + 15
3x = 60
x = 60/3
x = 20
b) 
Open brackets
7n - 20 = 36n + 9
7n - 36n = 20 + 9
- 29 n = 29
n = - 29/29
n = - 1
Therefore, from the given information, we can conclude that It is nearly impossible to visit the sun due to the degree of its temperature and radiation. Also, the value of x = 20 and the value of n = -1
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Based the density function of the observed outcome, the probability 
is equal to 0.1388.
<h3>What is a density function?</h3>
A density function can be defined as a type of function which is used to represent the density of a continuous random variable that lies within a specific range.
Given the following density function:
Next, we would calculate ;
![P(x\leq \frac{1}{3} )=\int\limits^\frac{1}{3} _0 {f(x)} \, dx \\\\P(x\leq \frac{1}{3} )=2 \int\limits^\frac{1}{3} _0 {(1-x)} \, dx \\\\P(x\leq \frac{1}{3} )=2|x-\frac{x^2}{2} |\limits^\frac{1}{3} _0\\\\P(x\leq \frac{1}{3} )=2[\frac{1}{3} -\frac{1}{2} (\frac{1}{3})^2]\\\\P(x\leq \frac{1}{3} )=2[\frac{1}{3} -\frac{1}{18}]\\\\P(x\leq \frac{1}{3} )=0.1388](https://tex.z-dn.net/?f=P%28x%5Cleq%20%5Cfrac%7B1%7D%7B3%7D%20%29%3D%5Cint%5Climits%5E%5Cfrac%7B1%7D%7B3%7D%20_0%20%7Bf%28x%29%7D%20%5C%2C%20dx%20%5C%5C%5C%5CP%28x%5Cleq%20%5Cfrac%7B1%7D%7B3%7D%20%29%3D2%20%5Cint%5Climits%5E%5Cfrac%7B1%7D%7B3%7D%20_0%20%7B%281-x%29%7D%20%5C%2C%20dx%20%5C%5C%5C%5CP%28x%5Cleq%20%5Cfrac%7B1%7D%7B3%7D%20%29%3D2%7Cx-%5Cfrac%7Bx%5E2%7D%7B2%7D%20%7C%5Climits%5E%5Cfrac%7B1%7D%7B3%7D%20_0%5C%5C%5C%5CP%28x%5Cleq%20%5Cfrac%7B1%7D%7B3%7D%20%29%3D2%5B%5Cfrac%7B1%7D%7B3%7D%20-%5Cfrac%7B1%7D%7B2%7D%20%28%5Cfrac%7B1%7D%7B3%7D%29%5E2%5D%5C%5C%5C%5CP%28x%5Cleq%20%5Cfrac%7B1%7D%7B3%7D%20%29%3D2%5B%5Cfrac%7B1%7D%7B3%7D%20-%5Cfrac%7B1%7D%7B18%7D%5D%5C%5C%5C%5CP%28x%5Cleq%20%5Cfrac%7B1%7D%7B3%7D%20%29%3D0.1388)
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