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3 years ago

14

Please help I'm in desperate need of assistance

1 answer:

ivanzaharov [21]3 years ago

7 0

Answer:

Step-by-step explanation: I think for figure 0 is 7.figure 1 is 9 and the growth is for every increase of the figure number it adds 2 for the tile number.

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Use the Pythagorean Theorem to find the missing length in the right triangle

Gelneren [198K]

Answer:

it depends

Step-by-step explanation:

If 17 is the hypotenuse

$c=17\\\\b=12\\\\a=?\\\\c^{2} =a^2+b^2\\\\17^2=a^2+12^2\\\\17^2-12^2=a^2\\\\(17-12)(17+12)=a^2\\\\5(27)=a^2\\\\a=\sqrt{9*3*5} \\\\a=3\sqrt{15} \\\\a=11.6$

if you are looking for the hypotenuse

$a=17\\\\b=12\\\\c=?\\\\a^2+b^2=c^2\\\\17^2+12^2=c^2\\\\289+144=c^2\\\\433=c^2\\\\c=\sqrt{433} \\\\c=20.8$

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3 years ago

Anyone wanna help me??

klasskru [66]

Answer

i believe it’s b

expiation

3 0

3 years ago

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nignag [31]

1/2 K - 3/5 is the answer. You’re welcome and Brainliest would be appreciated :)

5 0

3 years ago

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koban [17]

Answer:

$3m^{10}n^{-11}$

Step-by-step explanation:

Given the expression $\frac{(3m^{-1}n^{2})^{-4} }{(2m^{-2}n)^{3} }$ , we will use laws of indices to get the equivalent expression as shown below;

According to one of the law of indices,

$\frac{a^{m} }{a^{n} } = a^{m-n} \ and\ (a^{m})^{n} = a^{mn}$

$\frac{(3m^{-1}n^{2})^{-4} }{(2m^{-2}n)^{3} }\\= \frac{3m^{4}n^{-8} }{2m^{-6}n^{3} }\\= 3m^{(4-(-6))} * n^{-8-3}\\ = 3m^{10}n^{-11}$

This gives the required expression

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3 years ago

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polet [3.4K]

Answer:

i think the given triangle is equilateral triangle because all side are equal.

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2 years ago

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