Answer:
h(3) = 35
Step-by-step explanation:
Simplify h(t) = 16t - 4t - 1 to h(t) = 12t -1
Then, plug 3 into the t
h(3) = 12*3 - 1 = 36 - 1 = 35
Answer:
-7-y1=-4(2-x1)
Step-by-step explanation:
Point slope form is like this: y-y1=m(x-x1) where y is the y value, x is the x value, and m is the slope. You plug the values in.
Answer:
3
Step-by-step explanation:
Usually, when there is contamination the smallest amount can have huge ramifications in the data collected. In this scenario, if in a "clean" environment the trait is found in 2/10 frogs then anything above this number should be considered contaminated. This is because data above this ratio would be considered uncommon or rare and this unique occurrence can be most likely tied to the only new factor which would be the contamination. Therefore the minimum number of frogs with this trait in the sample would be 3.
<span>This problem is solved using the chain rule.
the area of the square is f(t) and the length of the side is g(t)
f(t)=g(t)^2
g'(t)=5
Using the chain rule
f'(t)=2*g(t)*g'(t)
The value of g(t) is sqrt(49) which is 7.
g'(t) is given as 5 cm/s
f'(t)=2*7*5=14*5=70cm^2/s</span>
