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Gnoma [55]
3 years ago
7

Which describes the relationship between the distance and the difference? The distance is always the opposite of the difference.

The distance is exactly the difference. The distance is the absolute value of the difference. The distance is not related to difference.
Mathematics
2 answers:
denpristay [2]3 years ago
5 0

Answer:

The distance is the absolute value of the difference

Step-by-step explanation:

Mekhanik [1.2K]3 years ago
5 0

Answer:

The distance is the absolute value of the difference.

Step-by-step explanation:

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From experience, it is known that on average 10% of welds performed by a particular welder are defective. if this welder is requ
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Binomial distribution can be used because the situation satisfies all the following conditions:1. Number of trials is known and remains constant (n)2. Each trial is Bernoulli (i.e. exactly two possible outcomes) (success/failure)3. Probability is known and remains constant throughout the trials (p)4. All trials are random and independent of the othersThe number of successes, x, is then given byP(x)=C(n,x)p^x(1-p)^{n-x}whereC(n,x)=\frac{n!}{x!(n-x)!}
Here we're given
p=0.10  [ success = defective ]
n=3

(a) x=0
P(x)=C(n,x)p^x(1-p)^{n-x}
=C(3,0)0.1^0(1-0.1)^{3-0}
=1(1)(0.729)
=0.729

(b) x=2
P(x)=C(n,x)p^x(1-p)^{n-x}
=C(3,2)0.1^2(1-0.1)^{3-2}
=3(0.01)(0.9)
=0.027

(c) x &ge; 2
P(x)=\sum_{x=2}^3C(n,x)p^x(1-p)^{n-x}
=P(2)+P(3)
=C(n,2)p^2(1-p)^{n-2}+C(n,3)p^3(1-p)^{n-3}
=C(3,2)0.1^2(1-0.1)^{3-2}+C(3,3)0.1^3(1-0.1)^{3-3}
=3(0.01)(0.9)+1(0.001)1
=0.027+0.001
=0.028


8 0
3 years ago
Help me please please
yanalaym [24]

Answer:

Hold on a sec i cant remember

3 0
2 years ago
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