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2 years ago

Given the function f(x) =5/4 x -5 solve for the X- and y- intercepts use the interprets to graph the function .

Mathematics

1 answer:

const2013 [10]2 years ago

4 0

Answer:

y intercept = -5

x intercept = 4

Step-by-step explanation:

f(x) can be substituted with y for this question.

y = 5/4x - 5

the way to solve for x intercept is to set y to 0 and solve for x

0 = 5/4x - 5

5 = 5/4x

multiply by four on both sides

20 = 5x

divide by five on both sides

4 = x

the way to solve for the y intercept is to set x to 0 and solve for y

y = 5/4(0) - 5

y = -5

you can then graph the points (4,0) and (0,-5) to create the line for the function.

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Studentka2010 [4]

Answer:

The area of the shaded portion of the figure is $9.1\ cm^2$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The shaded area is equal to the area of the square less the area not shaded.

There are 4 "not shaded" regions.

step 1

Find the area of square ABCD

The area of square is equal to

$A=b^2$

where

b is the length side of the square

we have

$b=4\ cm$

substitute

$A=4^2=16\ cm^2$

step 2

We can find the area of 2 "not shaded" regions by calculating the area of the square less two semi-circles (one circle):

The area of circle is equal to

$A=\pi r^{2}$

The diameter of the circle is equal to the length side of the square

$r=\frac{b}{2}=\frac{4}{2}=2\ cm$ ---> radius is half the diameter

substitute

$A=\pi (2)^{2}$

$A=4\pi\ cm^2$

Therefore, the area of 2 "not-shaded" regions is:

$A=(16-4\pi) \ cm^2$

and the area of 4 "not-shaded" regions is:

$A=2(16-4\pi)=(32-8\pi)\ cm^2$

step 3

Find the area of the shaded region

Remember that the area of the shaded region is the area of the square less 4 "not shaded" regions:

$A=16-(32-8\pi)=(8\pi-16)\ cm^2$

---> exact value

assume

$\pi =3.14$

substitute

$A=(8(3.14)-16)=9.1\ cm^2$

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3 years ago

AB has coordinates A(-5,9) and B(7,- 7). Points P, Q, and I are collinear

VMariaS [17]

Answer:

$\overline{QT}$

Step-by-step explanation:

We want to find the coordinates of a certain point C(x,y) such that C divides $A(x_1,y_1)$ and $B(x_2,y_2)$ in the ratio m:n=3:2

The x-coordinate is given by:

$x=\frac{mx_2+nx_1}{m+n}$

The y-coordinate is given by:

$y=\frac{my_2+ny_1}{m+n}$

AB has coordinates A(-5,9) and B(7,- 7)

We substitute the values to get:

$x=\frac{3*7+2*-5}{3+2}$

$x=\frac{21-10}{5}$

$x=\frac{11}{5}$

and

$y=\frac{3*-7+2*9}{3+2}$

$y=\frac{-21+18}{5}$

$y=-\frac{3}{5}$

Therefore C has coordinates $(\frac{11}{5},-\frac{3}{5})$

The line segment that contains C is $\overline{QT}$

See attachment.

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2 years ago