Answer: 5 km walking and 30 km by bus
Step-by-step explanation:
Yochanan walked from home to the bus stop at an average speed of 5 km / h. He immediately got on his school bus and traveled at an average speed of 60 km / h until he got to school. The total distance from his home to school is 35 km, and the entire trip took 1.5 hours. How many km did Yochanan cover by walking and how many did he cover by travelling on the bus?
walking - 5km/h bus - 60km/h
distance walking - d₁ distance bus - d₂
time walking - t₁ time bus - t₂
d₁ + d₂ = 35
t₁ + t₂ = 1.5
v = d/t
vwalking = d₁/t₁
5 = d₁/t₁ ⇒ d₁ = 5t₁
vbus = d₂/t₂
60 = d₂/t₂ ⇒ d₂ = 60t₂
d₁ + d₂ = 35 ⇒ 5t₁ + 60t₂ = 35
_________________________
5t₁ + 60t₂ = 35
t₁ + t₂ = 1.5 (*-5)
5t₁ + 60t₂ = 35
-5t₁ -5t₂ = -7.5 (+)
__________________________
55t₂ = 27.5
t₂ = 27.5/55 = 0.5 h
t₁ + t₂ = 1.5 ⇒ t₁ = 1.5 - 0.5 = 1h
d₁ = 5t₁ ⇒ d₁ = 5.1 = 5 km
d₂ = 60t₂ ⇒ d₂ = 30.0.5 = 30 km
Answer:
2.5
Step-by-step explanation:
because you can tell by the numbers and how close they are then u have to divide
Te answer would be q/2, or C. if you need further details dm me
⇒ x - 6 = 2x + 26
⇒ x = -32
⇒ This Equation has One Solution
So, It matches with A in Column B
2. 2 + 6x - 7 = 8 + 2x - 10 + 4x
⇒ 6x - 5 = 6x - 2
As, They are Equations of Parallel Lines. They never meet each other.
⇒ This Equation has No Solution
⇒ So, It matches with B in Column B
3. 15x + 25 = 15x + 10
As, They are Equations of Parallel Lines. They never meet each other.
⇒ This Equation has No Solution
⇒ So, It matches with B in Column B
4. 16 + 8x = 4(2x + 4)
⇒ 16 + 8x = 16 + 8x
As, Both Equations are Same. They Represent the Same Line.
⇒ This Equation has Infinite Number of Solutions
⇒ So, It matches with C in Column B
