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3 years ago

Please help please please help me help please

Mathematics

1 answer:

Nataly_w [17]3 years ago

8 0

Answer:

slope = -4

Step-by-step explanation:

rise/ run = 4/1, but slope always minus, so slope = -4

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A. x = 20, mZH = 62°, mZI = 89°, mZJ = 69°

Delicious77 [7]

Answer:

guy7p9;y

Step-by-step explanation:

6 0

3 years ago

Kacie bought x, number of pencils. She paid $0.91, including tax, per pencil. She gave the cashier $10 and received $6.36 back i

wel

Answer:

She purchased 4 pencils

Step-by-step explanation:

Here, we are to calculate the number of pencils bought given the information in the question.

The amount per pencil is $0.91. The total amount of this since she bought x number of pencils is $0.91 * x = $0.91x

Now, after paying $10, she was given $6.36 as change

what this means is that what the pencils cost is 10-6.36 = $3.64

Now we equate the cost in terms of x to this;

0.91x = 3.64

x = 3.64/0.91

x = 4 pencils

4 0

3 years ago

Read 2 more answers

Three kids, Alberto, Bernadette, and Carlos, decide to share 11 cookies. They wonder how many ways they could split the cookies

Luda [366]

Using the arrangements formula, it is found that they find 46200 ways.

<h3>What is the arrangements formula?</h3>

The number of arrangements of n elements is given by:

$A_n = n!$

If they repeat in $n_1, n_2, \cdots, n_n$ ways, the number of arrangements is given by:

$A_n^{n_1, n_2, \cdots, n_n} = \frac{n!}{n_1!n_2!\cdots n_n}$

In this problem, 11 elements are arranged with repetitions of 4, 3 and 3, hence:

$T = \frac{11!}{4!3!3!} = 46200$

They find 46200 ways.

More can be learned about arrangements at brainly.com/question/2259733

5 0

2 years ago

A veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses

Licemer1 [7]

Answer:

Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

Step-by-step explanation:

We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.

So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;

Z = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = average age of the random sample of horses with colic = 12 yrs

$\mu$ = average age of all horses seen at the veterinary clinic = 10 yrs

$\sigma$ = standard deviation of all horses coming to the veterinary clinic = 8 yrs

n = sample of horses = 60

So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P( $\bar X$ $\geq$ 12)

P( $\bar X$ $\geq$ 12) = P( $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ $\geq$ $\frac{12-10}{\frac{8}{\sqrt{60} } }$ ) = P(Z $\geq$ 1.94) = 1 - P(Z < 1.94)

= 1 - 0.97381 = 0.0262

Therefore, probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

4 0

3 years ago

What is the minum of two colors needed?

Alexus [3.1K]

4 colour needed for this…i think

8 0

2 years ago