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lora16 [44]
3 years ago
8

C) 40.3, 32.7, 40.29, 43.43,32.23 In Decreasing order please ​

Mathematics
1 answer:
iogann1982 [59]3 years ago
5 0

Answer:

32.7, 40.29, 40.3, 43.43

Step-by-step explanation:

Hope this helps =)

Correct me if I am wrong

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What is the linear function equation represented by the graph?
Angelina_Jolie [31]

Answer:

y=1/3x-4

Step-by-step explanation:

The point where the line intercepts the y-axis is the y-intercept and where the digit -4 comes from

1/3 comes from how many times the line rises (1) and run (3)

Hope this helps!

7 0
2 years ago
Whats 7+9+9+2<br><br> anyone wanna talk or rp<br><br><br> Math question
AfilCa [17]

☁️ Answer ☁️

7+9+9+2 = 27~

Hope it helps!~ ^-^

Explanation: hru m8? How's life?  ̄▽ ̄

8 0
3 years ago
Read 2 more answers
Construct a 90% confidence interval for μ1-μ2 with the sample statistics for mean calorie content of two​ bakeries' specialty pi
DIA [1.3K]

Answer:

The 90% confidence interval for the difference in mean (μ₁ - μ₂) for the two bakeries is; (<u>49</u>) < μ₁ - μ₂ < (<u>289)</u>

Step-by-step explanation:

The given data are;

Bakery A

\overline x_1<em> </em>= 1,880 cal

s₁ = 148 cal

n₁ = 10

Bakery B

\overline x_2<em> </em>= 1,711 cal

s₂ = 192 cal

n₂ = 10

\left (\bar{x}_1-\bar{x}_{2}  \right ) - t_{c}\cdot \hat \sigma \sqrt{\dfrac{1}{n_{1}}+\dfrac{1}{n_{2}}}< \mu _{1}-\mu _{2}< \left (\bar{x}_1-\bar{x}_{2}  \right ) + t_{c}\cdot \hat \sigma \sqrt{\dfrac{1}{n_{1}}+\dfrac{1}{n_{2}}}

df = n₁ + n₂ - 2

∴ df = 10 + 18 - 2 = 26

From the t-table, we have, for two tails, t_c = 1.706

\hat{\sigma} =\sqrt{\dfrac{\left ( n_{1}-1 \right )\cdot s_{1}^{2} +\left ( n_{2}-1 \right )\cdot s_{2}^{2}}{n_{1}+n_{2}-2}}

\hat{\sigma} =\sqrt{\dfrac{\left ( 10-1 \right )\cdot 148^{2} +\left ( 18-1 \right )\cdot 192^{2}}{10+18-2}}= 178.004321469

\hat \sigma ≈ 178

Therefore, we get;

\left (1,880-1,711  \right ) - 1.706\times178 \sqrt{\dfrac{1}{10}+\dfrac{1}{18}}< \mu _{1}-\mu _{2}< \left (1,880-1,711  \right ) + 1.706\times178 \sqrt{\dfrac{1}{10}+\dfrac{1}{18}}

Which gives;

169 - \dfrac{75917\cdot \sqrt{35} }{3,750} < \mu _{1}-\mu _{2}< 169 + \dfrac{75917\cdot \sqrt{35} }{3,750}

Therefore, by rounding to the nearest integer, we have;

The 90% C.I. ≈ 49 < μ₁ - μ₂ < 289

4 0
3 years ago
savannah bought two 24 packs of tim bits. she is hanging out with 4 friends. what is the greatest number of timbits each of them
lilavasa [31]
6.It is a rational quotient. You know because 24 tim bits divided by four friends equals six.
5 0
3 years ago
Just wondering if this is the correct answer...
vaieri [72.5K]
Yes, that should be correct, I am not to sure so don't take my answer as a full yes, but I think that looks correct.
8 0
3 years ago
Read 2 more answers
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