3 years ago

What is the constant of variation, k, of the direct variation, y = kx, through (–3, 2)?

Mathematics

1 answer:

UkoKoshka [18]3 years ago

8 0

Y = kx ⇒ k = y/x = 2/(-3) = -2/3

Answer: k = -2/3

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Answer:

$CSA = 660cm^2$ --- Curved Surface Area

$TSA = 968cm^2$ --- Total Surface Area

Step-by-step explanation:

Given

Shape: Cylinder

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$r = 7$ --- radius

Solving (a): The curved surface area (CSA)

This is calculated as:

$CSA = 2\pi rh$

This gives:

$CSA = 2 * \frac{22}{7} * 7 * 15$

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Solving (b): The total surface area (TSA)

This is calculated as:

$TSA = 2\pi r(h + r)$

This gives:

$TSA = 2 * \frac{22}{7} * 7 * (15 + 7)$

$TSA = 2 * 22 * (15 + 7)$

$TSA = 2 * 22 * 22$

$TSA = 968cm^2$

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