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Anika [276]
3 years ago
12

You need to find the width of the stream. You cannot measure the width directly, so you draw a diagram showing lengths that you

can measure. Your diagram contains two similar triangles, one in the stream and one on land. Use the diagram to find the width of the stream.

Mathematics
2 answers:
sergejj [24]3 years ago
3 0
I believe it is a) 22.4 feet.  I looked at the comparison between the 6 feet and the width of the lake and a) seemed to make the most sense.
weeeeeb [17]3 years ago
3 0

You are given that the diagram contains two similar triangles.

Two similar triangles have proportional sizes of corresponding sides.

Then the ratio between smaller legs is the same as the ratio between greater legs:

\dfrac{x}{6}= \dfrac{28}{7.5},\\ \\x=\dfrac{28\cdot 6}{7.5}=22.4\ ft.

Answer: correct choice is A.

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Please help me with this!!!
Dafna1 [17]

Answer:

option C is correct answer ..

Step-by-step explanation:

angle A + angle B + angle C = 180° ( by angle sum property of triangle )

3x + 4x-19+ 3x -1 = 180

10x + -20 = 180

10x = 180 +20 = 200

x = 200/10 = 20 °

angle A = 3× 20 = 60 °

angle B = 4× 20 - 1 9 = 61 °

angle C = 3× 20 -1 = 59 °

angle B is greatest so side opposite to it will be greatest in length ....so length of AC is greatest ....

so option C is the correct answer of this question ...

plz mark my answer as brainlist plzzzz vote me also as I have done this question by taking a lot of time Hope it will be helpful for you ....

5 0
3 years ago
I really need help at this. Pleas help!!
Alik [6]

Answer: x>-5

It is x is greater than or equal to -5

6 0
2 years ago
If a/2b =3/5 and 4b/3c=1/7, then a/c=<br> I will mark you brainlist whoever get this correct
ioda

Answer:

a/c=2/7 u are welcome thanks for ur help

7 0
3 years ago
What is 4^4+9-2:4^1(4592+281)^2 ?
Sliva [168]

Answer

-23745599/2

Step-by-step explanation:

3 0
3 years ago
Verify:<br>cos(2A)=(cotA-tanA)/cscAsecA​
kolbaska11 [484]

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identities

cot A = \frac{cosA}{sinA}, tanA = \frac{sinA}{cosA}, cscA  = \frac{1}{sinA}, secA = \frac{1}{cosA}

Consider the right side

\frac{cotA-tanA}{cscAsecA}

= \frac{\frac{cosA}{sinA}-\frac{sinA}{cosA}  }{\frac{1}{sinA}.\frac{1}{cosA}  }

= \frac{\frac{cos^2A-sin^2A}{sinAcosA} }{\frac{1}{sinAcosA} }

= \frac{cos^2A-sin^2A}{sinAcosA} × sinAcosA ( cancel sinAcosA )

= cos²A - sin²A

= cos2A

= left side ⇒ verified

5 0
3 years ago
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