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olchik [2.2K]
4 years ago
9

What is the surface area of this figure?Please help.

Mathematics
1 answer:
MakcuM [25]4 years ago
4 0

Answer:

109

Step-by-step explanation:

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What would be the first step you do to solve the equation below?<br><br><br><br> -19 = 15 - 6x
Westkost [7]

Answer:

you would transfer 15 to the other side

Step-by-step explanation:

-19=15-6x

-34=6x

6 0
3 years ago
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Find the mode(s) for the given sample data. The lengths (in inches) of each snake in the Clarmont Zoo's reptile house are shown
Contact [7]

The correct option is :   no mode

<u><em>Explanation</em></u>

The given data set is:  9, 15, 86, 13, 16, 101, 85, 10, 14, 17, 102

The <u>mode is the number that is repeated more often</u> than any other number in the data set.

But here we can see that all the numbers in this data set are different. That means <u>they appear only once</u>.

So, there will be 'no mode' in this set.

3 0
3 years ago
Find the Surface Area and Volume of Sphere with radius 12 cm.
Gnom [1K]
Radius:r=12cm\\\\Surface\ area:\\A=4\pi r^2\to A=4\pi\cdot12^2=4\pi\cdot144=576\pi\ (cm^2)\\\\Volume:\\V=\frac{4}{3}\pi r^3\to V=\frac{4}{3}\pi\cdot12^3=\frac{4}{3}\pi\cdot1728=4\pi\cdot576=2304\pi\ (cm^3)
8 0
3 years ago
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If x = 1 is a common root of ax² +ax + 2 = 0 and x² + x + b = 0 , then ab =
vodka [1.7K]

Answer:

ab = 2

Step-by-step explanation:

Given equations

ax² +ax + 2 = 0

x² + x + b = 0

root of both the equation

x= 1

then we can plug in x = 1 in both the equation

ax² +ax + 2 = 0                        x² + x + b = 0

a*1² +a*1 + 2 = 0                        1² + 1 + b = 0

a +a + 2 = 0                                 1 + 1 + b = 0

2a + 2 = 0                                    2 + b = 0

2a = -  2                                         b = -2

a = -2/2 = -1

Thus,

a = -1

b = -2

a*b = -1*-2 = 2

ab = 2

6 0
3 years ago
What is the answer? x+300=500 Will mark brainliest for high quality answers
cestrela7 [59]

Answer: x=  

3

500

​  

=166.667

Step-by-step explanation:

This deals with adding, subtracting and finding the least common multiple.

7 0
3 years ago
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