Answer:
c
Step-by-step explanation:
show me the problem and make me brainliest
Answer:
(4^-3)(x^-3) y^(18)
or
y^18/ (64 x^3)
Step-by-step explanation:
(4xy^-6)^-3
Distribute the exponent to all terms in the parentheses
(4^-3)(x^-3) (y^-6)^-3
a^ b^c = a^ (b*c)
(4^-3)(x^-3) y^(-6*-3)
(4^-3)(x^-3) y^(18)
If we do not want negative exponents
a ^ -b = 1/ a^b
y^18/( 4^3 x^3)
y^18/ (64 x^3)
Answer:
46
Step-by-step explanation:
Using PEMDAS (Parentheses, Exponents, Multiplication, Division, Addition, Subtraction), we get:
5 × 7 - 4² + 27 =
<em>Exponents</em>
5 × 7 - 16 + 27 =
<em>Multiplication</em>
35 - 16 + 27 =
<em>Subtraction</em>
19 + 27 =
<em>Addition</em>
46
Answer:
5 x + 3 = 23
Step-by-step explanation:
Answer:
2.35714285714
Step-by-step explanation:
Thank you!
