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satela [25.4K]
4 years ago
10

Simplify: (4xy^-6)^-3

(4xy^{-6} )^{-3}" alt="(4xy^{-6} )^{-3}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Zepler [3.9K]4 years ago
4 0

Answer:

(4^-3)(x^-3) y^(18)

or

y^18/ (64 x^3)

Step-by-step explanation:

(4xy^-6)^-3

Distribute the exponent to all terms in the parentheses

(4^-3)(x^-3) (y^-6)^-3

a^ b^c = a^ (b*c)

(4^-3)(x^-3) y^(-6*-3)

(4^-3)(x^-3) y^(18)

If we do not want negative exponents

a ^ -b = 1/ a^b

y^18/( 4^3 x^3)

y^18/ (64 x^3)

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