Answer:
if x=-1 then its is NOT in the domain of h.
Step-by-step explanation:
Domain is the set of values for which the function is defined.
we are given the function
h(x) = x + 1 / x^2 + 2x + 1
h(x) = x+1 /x^2+x+x+1
h(x) = x+1/x(x+1)+1(x+1)
h(x) = x+1/(x+1)(x+1)
h(x) = x+1/(x+1)^2
So, the function h(x) is defined when x ≠ -1
Its is not defined when x=-1
So, if x=-1 then its is NOT in the domain of h.
Answer:
((2a+b)/2 , a/2)
Step-by-step explanation:
The midpoint is the mean/average of both the x and y values.
Our x values are a+b and a
Our y values are a-b and b
The midpoint x value is (a+b + a ) /2 = (2a + b)/2
The midpoint y value is (a-b + b) /2 = (a)/2
The midpoint combines these two values to get ((2a+b)/2 , a/2) as our midpoint
Answer:
Step-by-step explanation:
The answer is '<span>f(x) is an odd degree polynomial with a positive leading coefficient'.
An odd degree polynomial with a positive leading coefficient will have the graph go towards negative infinity as x goes towards negative infinity, and go towards infinity as x goes towards infinity.
An even degree polynomial with a negative leading coefficient will have the graph go towards infinity as x goes toward negative infinity, and go towards negative infinity as x goes toward infinity.
g(x) would have a a positive leading coefficient with an even degree, as the graph goes towards infinity as x goes towards either negative or positive infinity.
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