Answer: 0.4667
Step-by-step explanation:
According to 68–95–99.7 rule , About 99.7% of all data values lies with in 3 standard deviations from population mean (
).
Here , margin of error = 3s , where s is standard deviation.
As per given , we have want our sample mean
to estimate μ μ with an error of no more than 1.4 point in either direction.
If 99.7% of all samples give an
within 1.4 , it means that

Divide boths ides by 3 , we get

Hence, So
must have 0.4667 as standard deviation so that 99.7 % 99.7% of all samples give an
within 1.4 point of μ .
Answer: 10.8
Step-by-step explanation: the pythagorean theorem is A sqaured or A^2 + B^2 or B squared equals C^2 or C squared so 10 squared as is the first number is 100 and 4 squared as is the second number is 16 add the two to get 116 but since your answer is squared you need to take the square root which means your answer is 10.7703296143 but since your rounding to the tenths place your answer is 10.8
The expression that can be used to represent the list price of the smartphone is 5179.99 * (1- 25%) and the value is 3884.9925
<h3>What expression can be used to represent the list price of the smartphone? </h3>
The given parameters are:
Discount = 25%
Sales price = 5179.99
The expression that can be used to represent the list price of the smartphone is
Expression = Sales price * (1- discount)
So, we have:
Expression = 5179.99 * (1- 25%)
Evaluate
Expression = 3884.9925
Hence, the expression that can be used to represent the list price of the smartphone is 5179.99 * (1- 25%) and the value is 3884.9925
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It would be the same as moving the decimal three to the right, and that applies to everything, not just the metric system.
Answer:
30
Step-by-step explanation:
30/-5=-6
due to integer rules the number would be negative