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2 years ago

661^5Solve it..........

Mathematics

2 answers:

Ket [755]2 years ago

4 0

Answer:

719,301

Step-by-step explanation:

Cause i know

satela [25.4K]2 years ago

3 0

$661 ^{5} \\ = 661 \times 661 \times 661 \times 661 \times 661 \\ = \boxed{ 126,184,873,719,301}$

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Pls answer this for me

nekit [7.7K]

Answer:

a 166 67/100

b 20 1/4

c 829 77/100

d 664 47/50

e 208 4/25

Step-by-step explanation:

you need to find the common denominator (the number on the bottom) so for the first one when can 10 = 100 if you multiply 10 x 10 you get 100 so multiply the entire fraction by 10 and you will get 10/100 so the equation would be 381 10/100 - 214 43/100 which equals 166 67/100 then just do the same thing for the rest of them

8 0

3 years ago

Find the distance between the points ( – 9, – 4) and ( – 4,8).

Dmitriy789 [7]

Answer:

$Distance=13\ units$

Step-by-step explanation:

Distance between two points: Distance between two pints $(x_1,y_1)\ and\ (x_2,y_2)$ is given by

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Distance between $(-9,-4)\ and\ (-4,8).$

$d=\sqrt{(-4-(-9))^2+(8-(-4))^2}\\\\d=\sqrt{(-4+9)^2+(8+4)^2}\\\\d=\sqrt{(5)^2+(12)^2}=\sqrt{25+144}\\\\d=\sqrt{169}\\\\d=13$

6 0

3 years ago

Help meeee I will give brainliest

Iteru [2.4K]

4.8, I hope this helps you, I answered this earlier. :)

4 0

3 years ago

Read 2 more answers

(a) Find a vector parallel to the line of intersection of the planes −4x+2y−z=1 and 3x−2y+2z=1.

valentinak56 [21]

Find the intersection of the two planes. Do this by solving for z in terms of x and y ; then solve for y in terms of x ; then again for z but only in terms of x.

-4x + 2y - z = 1 ==> z = -4x + 2y - 1

3x - 2y + 2z = 1 ==> z = (1 - 3x + 2y)/2

==> -4x + 2y - 1 = (1 - 3x + 2y)/2

==> -8x + 4y - 2 = 1 - 3x + 2y

==> -5x + 2y = 3

==> y = (3 + 5x)/2

==> z = -4x + 2 (3 + 5x)/2 - 1 = x + 2

So if we take x = t, the line of intersection is parameterized by

r(t) = ⟨t, (3 + 5t )/2, 2 + t⟩

Just to not have to work with fractions, scale this by a factor of 2, so that

r(t) = ⟨2t, 3 + 5t, 4 + 2t⟩

(a) The tangent vector to r(t) is parallel to this line, so you can use

v = dr/dt = d/dt ⟨2t, 3 + 5t, 4 + 2t⟩ = ⟨2, 5, 2⟩

or any scalar multiple of this.

(b) (-1, -1, 1) indeed lies in both planes. Plug in x = -1, y = 1, and z = 1 to both plane equations to see this for yourself. We already found the parameterization for the intersection,

r(t) = ⟨2t, 3 + 5t, 4 + 2t⟩

3 0

3 years ago

Which is the equation of a parabola with a directrix at y = −3 and a focus at (5, 3)? y = one twelfth(x − 5^)2

ankoles [38]

The equation of a parabola with a directrix at y = -3 and a focus at (5 , 3) is y = one twelfth (x - 5)² ⇒ 1st answer

Step-by-step explanation:

The form of the equation of the parabola is (x - h)² = 4p(y - k), where

The vertex of the parabola is (h , k)
The focus is (h , k + p)
The directrix is at y = k - p

∵ The focus of the parabola is at (5 , 3)

- Compare it with the 2nd rule above

∴ h = 5

∴ k + p = 3 ⇒ (1)

∵ The directrix is at y = -3

- By using the 3rd rule above

∴ k - p = -3 ⇒ (2)

Solve the system of equations to find k and p

Add equations (1) and (2) to eliminate p

∴ 2k = 0

- Divide both sides by 2

∴ k = 0

- Substitute the value of k in equation (1) to find p

∵ 0 + p = 3

∴ p = 3

Substitute the values of h , k , and p in the form of the equation above

∵ (x - 5)² = 4(3)(y - 0)

∴ (x - 5)² = 12 y

- Divide both sides by 12

∴ $\frac{1}{12}$ (x - 5)² = y

- Switch the two sides

∴ y = $\frac{1}{12}$ (x - 5)²

The equation of a parabola with a directrix at y = -3 and a focus at (5 , 3) is y = $\frac{1}{12}$ (x - 5)²

Learn more:

you can learn more about the quadratic equations in brainly.com/question/8054589

#LearnwithBrainly

8 0

3 years ago

661^5Solve it..........​

661^5Solve it..........