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saveliy_v [14]
3 years ago
9

Find the length of AC . Use that length to find the length ofCD.

Mathematics
2 answers:
svp [43]3 years ago
8 0
To find CD use the trig ratio that relates that side you're looking for to the angle you have and the other side you're given.  We have that the reference angle is 30, and we also have the hypotenuse of that right triangle on the left.  Solving for AC, which is the side opposite, we will use the sin ratio: sin(30)= \frac{AC}{10}.  10 sin(30) = AC.  Therefore, AC = 5.  Now that have that side measure, we can use that along with the reference angle in the right triangle on the right of 25 to find CD, which happens to be the side adjacent to the reference angle.  That satisfies our tangent ratio requirements.  Our ratio looks like this then: tan(25)= \frac{5}{CD}.  Solving for CD, CD= \frac{5}{tan(25)} and CD = 10.7, the third choice above.
Annette [7]3 years ago
3 0

Answer:

c

Step-by-step explanation:

i got it right on my test

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Answer please lot's of points.
Svetlanka [38]

Answer:

t≈8.0927

Step-by-step explanation:

h(t) = -16t^2 + 128t +12

We want to find when h(t) is zero ( or when it hits the ground)

0 =  -16t^2 + 128t +12

Completing the square

Subtract 12 from each side

-12  =  -16t^2 + 128t

Divide each side by -16

-12/-16  =  -16/-16t^2 + 128/-16t

3/4 = t^2 -8t

Take the coefficient of t and divide it by 8

-8/2 = -4

Then square it

(-4) ^2 = 16

Add 16 to each side

16+3/4 = t^2 -8t+16

64/4 + 3/4= (t-4)^2

67/4 = (t-4)^2

Take the square root of each side

±sqrt(67/4) =sqrt( (t-4)^2)

±1/2sqrt(67) = (t-4)

Add 4 to each side

4 ±1/2sqrt(67) = t

The approximate values for t are

t≈-0.092676

t≈8.0927

The first is before the rocket is launched so the only valid answer is the second one

3 0
3 years ago
Read 2 more answers
What is the vertex form of y=-2x2+4x + 3?
sukhopar [10]

Answer:

y=-2(x-1)^2+5

Step-by-step explanation:

we have

y=-2x^2+4x+3

This is the equation of a vertical parabola open downward

The vertex represent a maximum

Convert the quadratic equation into vertex form

step 1

Factor -2

y=-2(x^2-2x)+3

step 2

Complete the square

y=-2(x^2-2x+1)+3+2

y=-2(x^2-2x+1)+5

step 3

Rewrite as perfect squares

y=-2(x-1)^2+5 ----> equation in vertex form

The vertex is the point (1,5)

3 0
3 years ago
(√2+√3) ^2<br>answer faaaaaaaaaaaaast<br>​
ad-work [718]

Answer:

2.5

Step-by-step explanation:

7 0
3 years ago
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Which equation represents a linear function?
Blababa [14]

Answer:

The third one, y=x-3

Step-by-step explanation:

A linear equation is any equation that can be written in the form. ax+b=0. Meaning it will not have a radical or be squared.

4 0
3 years ago
Can someone help me
barxatty [35]

Answer:

y= (-6/5)x -2

Step-by-step explanation:

y=mx+b , where m is the slope, and b is the y -intercept

the y -intercept is where the line intersects the y-axis so b = -2

the slope m= y(rise) /x(run)  = 6/-5 = -6/5 ( to find the slope you have to know how to get from any point on the line to another point on the same line; start at point (0,-2) go up 6(y-rise) and to the left 5(x-run) at point (-5,4))

y= (-6/5)x -2

4 0
2 years ago
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