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gavmur [86]
2 years ago
13

If 3^x = 1, find the value of x.​

Mathematics
2 answers:
IrinaK [193]2 years ago
6 0

Answer:

0

Step-by-step explanation:

hope this helps darling

juin [17]2 years ago
3 0

\\ \sf\longmapsto 3^x=1

\\ \sf\longmapsto 3^x=3^0

\\ \sf\longmapsto x=0

Done

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At an ocean depth of 8 meters, a buoy bobs up and then down 5 meters from the ocean's depth. Sixteen seconds pass from the time
lisov135 [29]

Answer:

  See attached for a graph

Step-by-step explanation:

We're going to plot sea level as y=0 and a depth of 8 meters as y=-8.

The problem statement tells you the initial point (x=0) is at normal ocean depth (y=-8), so the first point you put into your sine tool is ...

  (x, y) = (0, -8)

The buoy takes 16 seconds to go from a high point to a low point, so the time to the first high point is half that, or x=8 seconds. That high point is 5 meters above its average depth, so is at y=-3.

The second point you will put into your sine tool is ...

  (x, y) = (8, -3)

7 0
3 years ago
Question 12 helllllllppppp plazzzzzzz
Eddi Din [679]

Answer:

Step-by-step explanation:

It says Renita takes minutes to ride half a mile.

She leaves 30 minutes before school.

Total distance is

               2\frac{1}{2} = \frac{1}{2}+ \frac{1}{2} +\frac{1}{2} +\frac{1}{2} +\frac{1}{2}\\

In

2\frac{1}{2} \ there \ are \ 5 \ times  \  \frac{1}{2} \ mile .\\

Therefore total time to reach school will be  5 x 5 = 25minutes.

Since she leaves 30minutes before school. She will reach 5minutes early before school.

8 0
3 years ago
14. What is the reflection image of (5, -3) across the line y = -x? (3, -5) (3, 5) (-3, 5) (-3, -5)
Nata [24]

Answer:

The reflection image of (5, -3) across the line y = -x is (3, -5).

Step-by-step explanation:

You can find the reflection equation by putting the value of x and y in the line given one by one.

5 0
3 years ago
he amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and s
sp2606 [1]

Complete question:

He amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and standard deviation 1.4 minutes. Suppose that a random sample of n equals 47 customers is observed. Find the probability that the average time waiting in line for these customers is

a) less than 8 minutes

b) between 8 and 9 minutes

c) less than 7.5 minutes

Answer:

a) 0.0708

b) 0.9291

c) 0.0000

Step-by-step explanation:

Given:

n = 47

u = 8.3 mins

s.d = 1.4 mins

a) Less than 8 minutes:

P(X

P(X' < 8) = P(Z< - 1.47)

Using the normal distribution table:

NORMSDIST(-1.47)

= 0.0708

b) between 8 and 9 minutes:

P(8< X' <9) =[\frac{8-8.3}{1.4/ \sqrt{47}}< \frac{X'-u}{s.d/ \sqrt{n}} < \frac{9-8.3}{1.4/ \sqrt{47}}]

= P(-1.47 <Z< 6.366)

= P( Z< 6.366) - P(Z< -1.47)

Using normal distribution table,

NORMSDIST(6.366)-NORMSDIST(-1.47)

0.9999 - 0.0708

= 0.9291

c) Less than 7.5 minutes:

P(X'<7.5) = P [Z< \frac{7.5-8.3}{1.4/ \sqrt{47}}]

P(X' < 7.5) = P(Z< -3.92)

NORMSDIST (-3.92)

= 0.0000

3 0
3 years ago
PLEASE HELP WILL MARK BRAINLIEST THANK U
Naddika [18.5K]

Answer:

89°

Step-By-Step Explanation:

<WYT is the angle 4

<UYW is the angle 5

since angle 4 and 5 are on the same line and

anngle 4 is 91°,

180° - 91° = 89°

This shows that <UYW is 89°

<em><u>If this helped, please consider picking this answer as the Brainliest Answer. Thank you!</u></em>

3 0
2 years ago
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