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Lunna [17]
3 years ago
11

Four different sets of objects contain 2, 5, 6, and 7 objects, respectively. How many unique combinations can be formed by picki

ng one object from each set?
Mathematics
2 answers:
Vika [28.1K]3 years ago
7 0

Answer: 420

Step-by-step explanation:

2*5*6*7 = 420

mario62 [17]3 years ago
3 0
The correct answer for the question that is being presented above is this one: "A. 960."<span>Four different sets of objects contain 2, 5, 6, and 7 objects, respectively. 
</span>
= 2 * 5 * 6 * 7
= 960

Here are the following choices:
A. 960 
<span>B. 141 </span>
<span>C. 23 </span>
D. 529
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svetlana [45]

Answer:

(8a)⁻¹⁸

1 / (8a)¹⁸

Step-by-step explanation:

(((8a)^6a)^4/4a))^-3

((8a)^6a*4/4a)^-3

((8a)^6)^-3

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(8a)⁻¹⁸

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2 years ago
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Step-by-step explanation:

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2 years ago
What is 5/6 times 4.
atroni [7]
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Whats the answer for this <br> 4b²+20b+25
WITCHER [35]
4b²+20b+25=0

Divide everything by 4 

b²+5b+ 6.25=0 

use the quadratic formula 
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x= (-5 + or - √5²-4*1*6.25) /2(1)
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7 0
3 years ago
Help easy math question!!!
bogdanovich [222]

Answer:

The length of the third side of the triangle is 30.

Step-by-step explanation:

Here is the formula for the Pythagorean Theorem:

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The hypotenuse, based on the problem, is 50. Anyways, let's get back to calculating!

We need to multiply 40 times 40 and 50 times 50.

40 times 40, or 40 squared, equals to 1600.

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