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Delvig [45]
2 years ago
5

What is the value of y? Y Y 60 O A. 120° B. 60° C. 40° O D. 30°

Mathematics
1 answer:
Grace [21]2 years ago
4 0

Answer:

B. 60°

Step-by-step explanation:

1. The measure of all angles in a triangle sum up to 180°. This means that y + y + 60 = 120.

2. (Solving)

Step 1: Simplify both sides of the equation.

  • (y+y)+(60)=180
  • 2y + 60 = 180

Step 2: Subtract 60 from both sides.

  • 2y + 60 - 60 = 180 - 60
  • 2y = 120

Step 3: Divide both sides by 2.

  • \frac{2y}{2}=\frac{120}{2}
  • y = 60

Step 4: Check if solution is correct.

  • (60)+(60)+60 = 180
  • 120 + 60 = 180
  • 180 = 180

Therefore, the answer is B. 60°.

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3 years ago
Given the circle with the equation (x - 3)2 + y2 = 49, determine the location of each point with respect to the graph of the cir
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To find out if a point is inside, on, or outside a circle, we need to substitute the ordered pair into the equation of the circle:
(x-xc)^2+(y-yc)^2=r^2
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If the left-hand side [(x-xc)^2+(y-yc)^2] is less than r^2, then point (x,y) is INSIDE the circle.  If the left-hand side is equal to r^2, the point is ON the circle.
Finally, if the left-hand side is greater than r^2, the point is OUTSIDE the circle.

For the given problem, we have xc=3, yc=0, or centre at (3,0), r=sqrt(49)=7
(x-xc)^2+(y-yc)^2=r^2 => (x-3)^2+y^2=7^2

A. (-1,1), 
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B. (10,0)
(x-3)^2+y^2=7^2 => (10-3)^2+0^2=49+0=49  [on circle]

C. (4,-8)
(x-3)^2+y^2=7^2 => (4-3)^2+(-8)^2=1+64=65 > 49  [outside circle]


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Step-by-step explanation:

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