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3 years ago

The sun of three consecutive integers is 60 find the integers

Mathematics

1 answer:

prohojiy [21]3 years ago

3 0

Answer:

let the three consecutive Integers be

x , x+1 , x+2

their sum is 60,

so,

x + x + 1 + x + 2 = 60

→ 3x + 3 = 60

→ 3x = 60 - 3 = 57

→ x = 57/3 = 19

therefore, 1st integer = 19

2nd integer = x + 1 = 19 + 1 = 20

3rd integer = x + 2 = 19 + 2 = 21

so,

the three consecutive Integers are 19 , 20 and 21.

hope this answer helps you dear... take care and may u have a great day ahead!

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3 years ago

Audryn left a $12 tip on a $68.73 restaurant bill. What percent tip did she leave? Round to the nearest tenth of a percent.

Fiesta28 [93]

So, if we take 68.73 to be the 100%, what is 12 in percentage off of it?

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seems Audryn is being generous, she probably got the silverware and the maple leaves tablecloth.

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A line is tangent to the circle x^2+y^2=41, at the point (-4,-5)

VashaNatasha [74]

If the equation of the circle is x^2+ y^2 = 41, we must first understand the parts of the equation.
A general circle's equation is (x-h)^2+(y-k)^2= r^2
(h.k) is the radius of the circle
r is the radius of the circle
Another useful fact to know is that tangent lines touch the circle at one point (4,5)

Since in our original equation there are no h or k values, we can assume that the center of the circle is (0,0).

The formula for slope is Y1-Y2
X1-X2
We can break this down with our two points (center and tangent)
(0,0) and (-4,-5)
(X1,Y1) and (X2,Y2)

therefore, we will put the equation as such
0-(-5)= 5 = 5
0-(-4)= 4  4

this is our slope from the center to the point of tangency.

We know that tangent lines are perpendicular to the radius, which we've already found the slope of. Perpendicular lines are opposite reciprocals of the line they are perpendicular to.

Therefore, we take our slope from center to the tangent, and make it opposite and then take the reciprocal of that slope, which will give us the slope of the tangent line itself. (note: reciprocal means flip the numerator and denominator)
5 = -5 = -4
4 4 5

Now, we have a point on the line, and the line's slope. We can use slope-intercept equation to find the equation of the line.

Slope-int y=mx+b
(x,y) is a point,
m is the slope
b is the y intercept ( the point where x=0, or where its on the y axis)

now we plug things in
(-4,-5) is our point,
-4 is our slope
5

-5=-4(-4)+b After we plug things in, solve for b
5

-5= 3.2+b

-1.8= b or b= 1 4
5

Now we just need to rewrite our equation with all our components.
(-4.-5) = point
-4 = slope
5
1 4 = y-intercept
 5

y=-4 x+ 1 4 This is the equation of the tangent line
 5 5

Hope that helped

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