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Tcecarenko [31]
2 years ago
11

1/3 of an obtuse angle is a(n):

Mathematics
1 answer:
Readme [11.4K]2 years ago
4 0

Answer:

acute

Step-by-step explanation:

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Find the solution set for this equation.
devlian [24]
Answer:
y= 0,-2

Hope this helps!
5 0
3 years ago
Find the value of x for which pll q.
klasskru [66]

Answer:

D) 9

Step-by-step explanation:

These angles are equal to each other because they’re alternate interior angles so:

9x + 8 = 15x - 46

9x - 15x = -46 - 8

-6x = -54

x = 9

7 0
3 years ago
(01.01) Kisha and Rae are asked to solve −5x − 14 = 2x + 7. Identify where one of them made an error.
lora16 [44]
It's A. 
Rae made the error when she added 7. 
the equation should be:
<span>-14 - 7 = 7x + 7 - 7 </span>
3 0
4 years ago
Read 2 more answers
Which of the following sequences of transformation is used to obtain figure A’B’C’D’ from ABCD?
weeeeeb [17]

Answer:

Most likely (B)

Step-by-step explanation:

Points of ABCD:

A (3,1)

B (3,4)

C (5,5)

D (5,2)

The algebraic rule for reflecting across the y axis:

(x,y) ---> (-x, y)

Points of ABCD after being reflected: (shown by figure 2)

A (-3, 1)

B (-3, 4)

C (-5, 5)

D (-5, 2)

Then, the figure got translated two units to the left, resulting in figure F in the picture, and A’B’C’D’ in the question.

Points of ABCD after being translated by (x-2, y) : (shown by figure F)

A (-5, 1)

B (-5, 4)

C (-7, 5)

D (-7, 2)

This should be the coordinates of A’B’C’D’.

7 0
4 years ago
If sinA+cosecA=3 find the value of sin2A+cosec2A​
Irina18 [472]

Answer:

\sin 2A + \csc 2A = 2.122

Step-by-step explanation:

Let f(A) = \sin A + \csc A, we proceed to transform the expression into an equivalent form of sines and cosines by means of the following trigonometrical identity:

\csc A = \frac{1}{\sin A} (1)

\sin^{2}A +\cos^{2}A = 1 (2)

Now we perform the operations: f(A) = 3

\sin A + \csc A = 3

\sin A + \frac{1}{\sin A} = 3

\sin ^{2}A + 1 = 3\cdot \sin A

\sin^{2}A -3\cdot \sin A +1 = 0 (3)

By the quadratic formula, we find the following solutions:

\sin A_{1} \approx 2.618 and \sin A_{2} \approx 0.382

Since sine is a bounded function between -1 and 1, the only solution that is mathematically reasonable is:

\sin A \approx 0.382

By means of inverse trigonometrical function, we get the value associate of the function in sexagesimal degrees:

A \approx 22.457^{\circ}

Then, the values of the cosine associated with that angle is:

\cos A \approx 0.924

Now, we have that f(A) = \sin 2A +\csc2A, we proceed to transform the expression into an equivalent form with sines and cosines. The following trignometrical identities are used:

\sin 2A = 2\cdot \sin A\cdot \cos A (4)

\csc 2A = \frac{1}{\sin 2A} (5)

f(A) = \sin 2A + \csc 2A

f(A) = \sin 2A +  \frac{1}{\sin 2A}

f(A) = \frac{\sin^{2} 2A+1}{\sin 2A}

f(A) = \frac{4\cdot \sin^{2}A\cdot \cos^{2}A+1}{2\cdot \sin A \cdot \cos A}

If we know that \sin A \approx 0.382 and \cos A \approx 0.924, then the value of the function is:

f(A) = \frac{4\cdot (0.382)^{2}\cdot (0.924)^{2}+1}{2\cdot (0.382)\cdot (0.924)}

f(A) = 2.122

8 0
3 years ago
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