Question

What's the equation of the line parallel to the equation 3x + y =6 and that passes through the point (-6, -1) .

Answer 1

Answer:

y = - 3x - 19

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange 3x + y = 6 into this form

Subtract 3x from both sides

y = - 3x + 6 ← in slope- intercept form

with slope m = - 3

• Parallel lines have equal slopes, hence

y = - 3x + c ← is the partial equation

To find c substitute (- 6, - 1) into the partial equation

- 1 = 18 + c ⇒ c = - 1 - 18 = - 19

y = - 3x - 19 ← is the equation of the parallel line

Answer 2

your formula will ALWAYS be Y=MX+B

3x + Y = 6

subtract 3x from each side

Y = -3x + 6

you’ll use rise over run, 1/3 will be your ratio.