The formula in terms of h is h = 3V/s^2 and the value of h is 5
<h3>How to write the formula in terms of h?</h3>
The equation is given as
V = 1/3s^2h
Divide both sides of the equation by 1/3s^2
So, we have
h = 3V/s^2
The given parameters are
V = 60 and s = 6
So, we have:
h = 3 * 60/6^2
Evaluate
h = 5
Hence, the formula in terms of h is h = 3V/s^2 and the value of h is 5
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Answer:
The object will hit the ground after 10.308 seconds.
Step-by-step explanation:
h(t) = -16t² + 1700
If you graphed this function, the object would be shown hitting the ground when it crosses the x-axis, in other words, when h = 0. So, to find the answer, just set h(t) equal to 0 and solve.
-16t² + 1700 = 0 Plug this into a calculator if you have one.
t = -10.308 and t = 10.308
Since time can't be negative, your answer will be the positive value, 10.308.
240, you just add a zero to 24, I don't know what you mean by zero the hero of 4 square, hope this helps!
Answer:
t:
meaning any number can substitute t and it would be the same answer.
