What is the limit in miles per hour if the speed limit is 55 km/hr??

garik1379 [7]

Answer: no

Step-by-step explanation: here are all the ratios equivalent to 18:6 18 : 636 : 1254 : 1872 : 2490 : 30108 : 36126 : 42144 : 48162 : 54180 : 60198 : 66216 : 72234 : 78252 : 84270 : 90288 : 96306 : 102324 : 108342 : 114360 : 120378 : 126396 : 132414 : 138432 : 144450 : 150468 : 156486 : 162504 : 168522 : 174540 : 180558 : 186576 : 192594 : 198612 : 204630 : 210648 : 216666 : 222684 : 228702 : 234720 : 240738 : 246756 : 252774 : 258792 : 264810 : 270828 : 276846 : 282864 : 288882 : 294900 : 300918 : 306936 : 312954 : 318972 : 324990 : 3301008 : 3361026 : 3421044 : 3481062 : 3541080 : 3601098 : 3661116 : 3721134 : 3781152 : 3841170 : 3901188 : 3961206 : 4021224 : 4081242 : 4141260 : 4201278 : 4261296 : 4321314 : 4381332 : 4441350 : 4501368 : 4561386 : 4621404 : 4681422 : 4741440 : 4801458 : 4861476 : 4921494 : 4981512 : 5041530 : 5101548 : 5161566 : 5221584 : 5281602 : 5341620 : 5401638 : 5461656 : 5521674 : 5581692 : 5641710 : 5701728 : 5761746 : 5821764 : 5881782 : 5941800 : 600

https://goodcalculators.com/ratio-calculator/

3 0

2 years ago

Read 2 more answers

Matt, the coordinator at the local emergency food hamper program, noticed the following trends: typically 200 hampers were distr

photoshop1234 [79]

Answer:

<em>793 food hampers were distributed</em>

Step-by-step explanation:

We need to find how many food hampers were distributed in a typical week, knowing that

200 hampers were distributed on Mondays

40 fewer hampers were distributed on Tuesdays than on Mondays, thus:

160 hampers were distributed on Tuesdays

on Wednesdays, the volume is 1.3 times Tuesday’s volume, thus 160*1.3=

208 hampers were distributed on Wednesdays

on Thursdays the number of hampers distributed was 3/4 of Monday’s volume, thus 3/4*200=

150 hampers were distributed on Thursdays

on Fridays, 50% of Thursday’s volume was distributed, therefore 50%*150=

75 hampers were distributed on Fridays

The total number of food hampers distributed in the week is

200+160+208+150+75=793

793 food hampers were distributed

4 0

3 years ago

The lengths of the sides of a triangle are 5, 12, and 13. What is the length of the altitude drawn to the side with length equal

mario62 [17]

Answer: using A= bh/2 THe height is 9.23

Step-by-step explanation: First, with the Right Angle at the bottom, usr the sides to compute the area: 12*5=60

THen Imagine the side=13 as the base, so you have b=13 for the formula

use the formula A= bh/2

60 = 13h/2 ==> 2(60) =13h --> 120/13 = h

h = 9.23

5 0

2 years ago

Read 2 more answers

Sketch the equilibrium solutions for the following DE and use them to determine the behavior of the solutions.

GREYUIT [131]

Answer:

$y=\dfrac{1}{1-Ke^{-t}}$

Step-by-step explanation:

Given

The given equation is a differential equation

$\dfrac{dy}{dt}=y-y^2$

$\dfrac{dy}{dt}=-(y^2-y)$

By separating variable

⇒ $\dfrac{dy}{(y^2-y)}=-t$

$\left(\dfrac{1}{y-1}-\dfrac{1}{y}\right)dy=-dt$

Now by taking integration both side

$\int\left(\dfrac{1}{y-1}-\dfrac{1}{y}\right)dy=-\int dt$

⇒ $\ln (y-1)-\ln y=-t+C$

Where C is the constant

$\ln \dfrac{y-1}{y}=-t+C$

$\dfrac{y-1}{y}=e^{-t+c}$

$\dfrac{y-1}{y}=Ke^{-t}$

$y=\dfrac{1}{1-Ke^{-t}}$

from above equation we can say that

When t will increases in positive direction then $e^{-t}$ will decreases it means that ${1-Ke^{-t}}$ will increases, so y will decreases. Similarly in the case of negative t.

4 0

3 years ago

mike began tiling his bathroom floor. he completed the top edge and left egde of the floor each peice is a square that has a sid

mafiozo [28]

It will be 25 because you have to multiply

6 0

2 years ago