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dsp73
3 years ago
15

Helpp! who ever gets it right gets brainliest!

Mathematics
1 answer:
sertanlavr [38]3 years ago
3 0

Answer:

1. 14

2. 5

3. 18

4. 16

5. 37

6. 26

7. 23

8. -10

9. 4

10. -54

Some questions are wrong so i answered what i understood. And giving me brainest will be helpful.

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WILL GIVE BRAINLIEST GIVE CORRECT ANSWER
OlgaM077 [116]
Your answer is correct
4 0
3 years ago
Read 2 more answers
Solve each system by graphing y=-x+5 and y=2x-4
makkiz [27]
In order to graph y=-x+5, make a table and plug in values of x to find y. to find your points, use x,y. 
x: 1  y: 4
x: 2  y: 3
x:3  y: 2
x: 2  y:1
these are the first four points for the first equation. to plug in, use ramdom numbers for x, such as 1, 2, and 3. y= -(1) +5
7 0
3 years ago
The circumference of a circle is 46.129 what is the diameter
inysia [295]

Answer:

The diameter is 14.68

Step-by-step explanation:

To get the diameter of a diameter from a given circumference, you just have to divide the circumference by Pi, as follows:

D=46.129/Pi

D=14.68

7 0
3 years ago
PLEASE HELP ME ASAP?!?
Blababa [14]

Answer:

f(x) = \frac{1}{4}x^{2}  > f(x) = -0.5x² > f(x) = x²

Step-by-step explanation:

In a quadratic function leading coefficient decides the width of a graph.

In simpler words, leading coefficient decides the vertical stretch of the graph.

Higher the value of leading coefficient, higher the vertical stretch.

When a graph is vertically stretched it becomes narrower.

(Note: Minus sign of the coefficient decides the opening of the graph, upwards or downwards)

Therefore, f(x) = x² having coefficient = 1 is the narrowest and f(x) = \frac{1}{4}x^{2} will be the widest.

So the descending order will be,

f(x) = \frac{1}{4}x^{2}  > f(x) = -0.5x² > f(x) = x²

5 0
4 years ago
PLEASE HELP
lisabon 2012 [21]

Step-by-step explanation:

The figure below shows a portion of the graph of the function j\left(x\right) \ = \ 4^{x-2}, hence the average rate of change (slope of the blue line) between the x and x+h is

                     \text{Average rate of change} \ = \ \displaystyle\frac{\Delta y}{\Delta x} \\ \\ \rule{3.7cm}{0cm} = \dsiplaystyle\frac{f\left(x+h\right) \ - \ f\left(x\right)}{\left(x \ + \ h \right) \ - \ x} \\ \\ \\  \rule{3.7cm}{0cm} = \displaystyle\frac{f\left(x + h\right) \ - \ f\left(x\right)}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{4^{x+h-2} \ - \ 4^{x-2}}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{4^{x-2+h} \ - \ 4^{x-2}}{h}

                                                            \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{\left(4^{x-2}\right)\left(4^{h}\right) \ - \ 4^{x-2}}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{\left(4^{x-2}\right)\left(4^{h} \ - \ 1 \right)}{h}

7 0
2 years ago
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