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AURORKA [14]
3 years ago
10

Are constants like terms

Mathematics
1 answer:
kondaur [170]3 years ago
7 0

Step-by-step explanation:

yes , all constant are like terms.

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Find the equation of the line. <br> Please need help badly!!
hoa [83]

Answer:

lets consider two end points are the marked points ,

Then ,

(1,5)=x1,y1

(-1,-3)=x2,y2

line passes through point(1,0)=x3,y3

slope of line ,m = (y2-y1)/(x2-x1)

= (-3-5)/(-1-1)

=4

Eqn of line is:

y-y3=m(x-x3)

y-0 = 4(x-1)

y=4x-4

4x-y=4 is reqyuired eqn..

Step-by-step explanation:

Problem may arise due to calculation but plz check it ...

7 0
3 years ago
Identify the slope of the given line.<br><br> y=x-5
laiz [17]

Answer:

m is the slope and b is the y-intercept. Therefore, for the equation y=x+5 , the slope is 1 , and the y-intercept is 5

Step-by-step explanation:

7 0
3 years ago
(1 point) let a=⟨−4,−3,2⟩a=⟨−4,−3,2⟩. find a unit vector in the same direction as aa.
sergij07 [2.7K]
A unit vector in the direction of a would be the vector a multiplied by a factor such that the length of vector a is unity.
The magnitude of a is given by:
|a|
=sqrt(4^2+3^2+2^2)   [ I got lazy instead of writing (-4)^2+(-3)^2+2^2]
=sqrt(29).

So the univector is a/sqrt(29), or (-4/sqrt(29),-3/sqrt(29), 2/sqrt(29), or simply (-4,-3,2)/sqrt(29).

8 0
3 years ago
Plz help 20 points!! note: there is more than one answer!!
Wittaler [7]
D, the number inside of the absolute lines are just the exact same number in there but just positive. If the number was positive the number would still be the number:

|100| = 100
|-100| = 100

4 0
3 years ago
How many permutations are possible for 13 objects taken 6 at a time?
Anarel [89]

Answer:

  1,235,520

Step-by-step explanation:

13P6 = 13!/(13-6)! = 13·12·11·10·9·8 = 1,235,520

__

There are 13 ways to choose the first object, 12 ways to choose the second, 11 ways to choose the third, and so on. The 6th object can be chosen 8 ways.

The total number of permutations is the product of all these ways:

  13·12·11·10·9·8 = 1,235,520

7 0
3 years ago
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