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muminat
3 years ago
12

Determine whether each relation is a function

Mathematics
1 answer:
Alex3 years ago
7 0

Step-by-step explanation:

(2,4),(3,5),(4,6),(5,8) (1,4),(2,3),(3,-6),(-3,6)

is NOT a function, because some x values (2 and 3) have more than one associated result value (4, 3 and 5, -6).

(1,5),(1,7),(1,-5),(1,-7) (0,4),(1,4),(2,4),(3,4)

is NOT a function as the x value 1 has more than 1 associated result values (5, 7, -5, -7, 4).

x² = y + 1

y = x² - 1

this is a function. for any value of x we get exactly one result value.

xy = 1

y = 1/x

this is a function. for any value of x we get exactly one result value. but we do need to exclude x=0.

if we cannot do that, then it is NOT a function, because x=0 has no associated result value.

x = 3

is NOT a function, because although there is only one valid x value (3), there are infinitely many possible y result values associated with this x value (y can be "anything").

y = -2

this is a function. for any value of x we get exactly one result value (constantly -2).

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Answer:

health inspector - every 7 days.

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Step-by-step explanation:

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3 years ago
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6 0
3 years ago
Mario invested $475 in $45 and $25 stock shares. The number of $25 shares was 5 less than 3 times the number of $45 shares. How
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\text{Answer : Number of \$45 shares} =120

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Explanation:

Let Number of $45 shares be x

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\text{Number of \$45 shares} =120

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