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2 years ago

Please I don't understand help me

Mathematics

1 answer:

Murrr4er [49]2 years ago

6 0

Answer:

6.2 seconds

Step-by-step explanation:

To translate into math, the question is asking you "for what approximate t value does h = 0?" In order to solve, you can plug in 0 for h and solve for t.

0 = -16t^2 + 620

-620 = -16t^2

620 = 16t^2

38.75 = t^2

$\sqrt{38.75}$ = t

6.2 ~~ t (rounding to the nearest tenth)

Don't forget your units!

Let me know if you need anything explained in more detail; I'm happy to help.

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soldier1979 [14.2K]

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3 years ago

Plsss help me with this question!!! Will mark the best answer brainliest!!

nata0808 [166]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Can someone help me?

zheka24 [161]

We can Notice that : Number of Cells growth is a Geometric Sequence

That is : 1 , 2 , 4 , 8 , 16. . . . .

We know that : nth term in a Geometric Sequence is = a.rⁿ⁻¹

where a is the first term

r is the common ratio, which is given by ratio of 2nd term to 1st term

For the above Sequence, a = 1 and r = 2

Given : nth term over 1000

⇒ 1.2ⁿ⁻¹ = 1024

⇒ 2ⁿ⁻¹ = 2¹⁰

⇒ n - 1 = 10

⇒ n = 11

We can Notice that : Number of Hours is a Arithmetic Sequence

That is : 0 , 3 , 6 , 9 , 12

We know that : nth term in a Arithmetic Sequence is = a + (n - 1)d

where a is the first term

r is the common difference, which is given by difference between 2nd term and 1st term

For the above Sequence, a = 0 and r = 3 - 0 = 3

we need to find the number of hours, which is when : n = 11

⇒ 0 + (11 - 1)3

⇒ 10(3)

⇒ 30

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4 0

3 years ago

Kari picked 23 bunches of flowers from her garden. Each bunch had the same number of flowers. After she gave 46 flowers away, sh

Aleks [24]

Answer:

8 flowers in each bunch

Step-by-step explanation:

From this information, we can make the equation:

$23b-46=138$

Where $b$ is the number of flower in each bunch.

$23b-46=138$

<em>Add 46 to both sides</em>

$23b=184$

<em>Divide both sides by 23</em>

$b=8$

There are 8 flowers in each bunch.

6 0

3 years ago

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your grades on tests 1 2 and 4 are 82 76 and 90. unfortunately you cut the third test and received a 0. If you have one test lef

Dmitrij [34]

Answer: No, he can't pass the course.

Explanation:

Since we have given that

Marks on tests 1, 2, and 4 are given by

82, 76, 90 respectively.

Unfortunately, he cut the third test and receive a 0.

According to question, we have given that passing grade for the course is 70, and his one test left to take ,

Let the marks obtained in fifth test be x

So,

$\frac{82+76+90+0+x}{5}=70\\\\248+x=5\times 70=350\\\\x=350-248\\\\x=102$

And it is not possible to get 102 over 100.

so, he can't still pass the course.

Hence, No, he can't pass the course.

8 0

3 years ago