I think the answer is B Mean or median because there is no outlier.
You are going to use the cos trig function as you have the adjacent side and the hypotenuse.
Cos^-1(12/13)=angle x
22.62
Line TU is 2 times OL, so 2(2x-14) = x+2.
4x-28 = x + 2
4x=x+30
3x=30
x=10
F(x)=(3x^2+2x-5)/(x-4)
f(x)=(3x+5)(x-1)/(x-4)
x-4|(3x^2+2x-5)
(x-4)3x
3x^2+2x-5-(3x^2-12x)
(x-4)3x+14
14x-5-(14x-56)
51
Oblique=3x+14