Answer:
y- intercept --> Location on graph where input is zero
f(x) < 0 --> Intervals of the domain where the graph is below the x-axis
x- intercept --> Location on graph where output is zero
f(x) > 0 --> Intervals of the domain where the graph is above the x-axis
Step-by-step explanation:
Y-intercept: The y-intercept is equivalent to the point where x= 0. 'x' is the input variable in an equation, therefore the y-intercept is where the input, or x, is equal to 0.
f(x) <0: Notice the 'lesser than' sign. This means that the value of f(x), or 'y', is less than 0. This means that this area consists of intervals of the domain below the x-axis.
X-intercept: The x-intercept is the location of the graph where y= 0, or the output is equal to 0.
f(x) >0: In this, there is a 'greater than' sign. This means that f(x), or 'y', is greater than 0. Therefore, this consists of intervals of the domain above the x-axis.
The y-intercept is (0,12), or just 12, hope this helps
Answer:
m=1
Step-by-step explanation:
12m+5=17
-5 -5
12m=12
m=1
The number would stay the same because, for example, 6 - 0 can't be 0 so it would be 6.
Answer:
52 quarters, 42 dimes
Step-by-step explanation:
Let's call the number of quarters q, and the number of dimes d.
q+d=94
0.25q+0.1d=17.20
Subtract q from both sides of the first equation to isolate d:
d=94-q
0.25q+0.1(94-q)=17.20
0.25q+9.4-0.1q=17.20
0.15q=7.8
q=52
d=94-q=42
Hope this helps!
