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2 years ago

11

The original price of a DVD is represented by the variable x. If the DVD is discounted 45%, write a subtraction expression and a

multiplication expression to represent its sale price.
What is the multiplication expression?

1 answer:

Sophie [7]2 years ago

8 0

Answer:

Sale price = x - 0.45x

Step-by-step explanation:

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Francisco has a savings account balance of 2,033.88. The interest rate on the account is 2.9% compounded monthly. If he opened t

inna [77]

Let P = the value of the initial deposit.

Given:
A = 2,033.88, the current amount
r = 2.9% = 0.029, interest rate
n = 12, compounding interval
t = 9 years

Then
$A=P(1+ \frac{r}{n})^{nt}$

That is,
P(1 + 0.029/12)¹⁰⁸ = 2203.88
1.2978P = 2203.88
P = $1,698.17

Answer: $1,698.17

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3 years ago

Write the formula that shows the dependence of:<br> HELP PLEASE

Arlecino [84]

$\qquad\qquad\huge\underline{{\sf Answer}}$

$\textbf{Volume of a cube can be represented as :}$

$\textsf{ side³}$

$\textsf{And the side length is given as a}$

$\textsf{So, volume of the given cube is :}$

$\textsf{V = a³ }$

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2 years ago

What substation should be used to rewrite 4x^4-21z^2+20=0

elena-s [515]

\left[x _{4}\right] = \left[ \frac{ - \left( -1\right) ^{\frac{3}{4}}\,\sqrt[4]{\left( 20 - 21\,z^{2}\right) }}{\sqrt[4]{4}}\right][x4]=[4√4−(−1)434√(20−21z2)]
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4 years ago

Suppose the roots of the polynomial $x^2 - mx + n$ are positive prime integers (not necessarily distinct). Given that $m < 20

Vsevolod [243]

Answer:

<em>18</em> values for n are possible.

Step-by-step explanation:

Given the quadratic polynomial:

$x^2 - mx + n$

such that:

Roots are positive prime integers and

$m < 20$

To find:

How many possible values of $n$ are there ?

Solution:

First of all, let us have a look at the sum and product of a quadratic equation.

If the quadratic equation is:

$Ax^{2} +Bx+C$

and the roots are: $\alpha$ and $\beta$

Then sum of roots, $\alpha+\beta = -\frac{B}{A}$

Product of roots, $\alpha \beta = \frac{C}{A}$

Comparing the given equation with standard equation, we get:

A = 1, B = -m and C = n

Sum of roots, $\alpha+\beta = -\frac{-m}{1} = m$

Product of roots, $\alpha \beta = \frac{n}{1} = n$

We are given that $m$

$\alpha$ and $\beta$ are positive prime integers such that their sum is less than 20.

Let us have a look at some of the positive prime integers:

2, 3, 5, 7, 11, 13, 17, 23, 29, .....

Now, we have to choose two such prime integers from above list such that their sum is less than 20 and the roots can be repetitive as well.

So, possible combinations and possible value of $n (= \alpha \times \beta)$ are:

$1.\ 2, 2\Rightarrow n = 2\times 2 = 4\\2.\ 2, 3 \Rightarrow n = 6\\3.\ 2, 5 \Rightarrow n = 10\\4.\ 2, 7\Rightarrow n = 14\\5.\ 2, 11 \Rightarrow n = 22\\6.\ 2, 13 \Rightarrow n = 26\\7.\ 2, 17 \Rightarrow n = 34\\8.\ 3, 3\Rightarrow n = 3\times 3 = 9\\9.\ 3, 5 \Rightarrow n = 15\\10.\ 3, 7 \Rightarrow n = 21\\$

$11.\ 3, 11\Rightarrow n = 33\\12.\ 3, 13 \Rightarrow n = 39\\13.\ 5, 5 \Rightarrow n = 25\\14.\ 5, 7 \Rightarrow n = 35\\15.\ 5, 11 \Rightarrow n = 55\\16.\ 5, 13 \Rightarrow n = 65\\17.\ 7, 7 \Rightarrow n = 49\\18.\ 7, 11 \Rightarrow n = 77$

So,as shown above <em>18 values for n are possible.</em>

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3 years ago

Please solve the system of equations below thank you<br> explain if u can

ivanzaharov [21]

First let’s try to cancel out the x
5x + -5x = 0
Add the y and the numbers together
-3y + -2y = -5y
26 + -16 = 10
-5y = 10
y = -2
Use y=-2 in one of the equations
-3(-2) + 5x = 26
6 + 5x = 26
5x = 20
X = 4

So
Y= -2
X= 4

https://mathsmadeeasy.co.uk/gcse-maths-revision/simultaneous-equations-gcse-maths-revision/

Check this link out for more help!

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2 years ago