Question

A gun with a muzzle velocity of 1500 feet per second is fired at an angle of 6 degrees with the horizontal. Find the vertical and horizontal components of the velocity to the nearest whole number.

Answer 1

Answer:

The vertical component of velocity is 156 feet per second

The horizontal component of velocity 1491 feet per second .

Step-by-step explanation:

Given as :

The velocity of gun = v = 1500 feet per sec

The angle made by gun with horizontal = Ф = 6°

Let The vertical component of velocity = $v__y$

Let The horizontal component of velocity = $v__x$

Now, According to question

The vertical component of velocity = v sin Ф

i.e  $v__y$ = v sin Ф

Or , $v__y$ = 1500 ft/sec × sin 6°

Or , $v__y$ = 1500 ft/sec × 0.104

∴  $v__y$ = 156 feet per second

So, The vertical component of velocity = $v__y$ = 156 feet per second

Now, Again

The horizontal component of velocity = v cos Ф

i.e  $v__x$ = v cos Ф

Or , $v__x$ = 1500 ft/sec × cos 6°

Or , $v__x$ = 1500 ft/sec × 0.994

∴  $v__x$ = 1491 feet per second

So, The horizontal component of velocity = $v__y$ = 1491 feet per second

Hence,The vertical component of velocity is 156 feet per second

And The horizontal component of velocity 1491 feet per second . Answer