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Serjik [45]
3 years ago
12

Please help!!!!!

Mathematics
1 answer:
Art [367]3 years ago
6 0
The answer to the question is a
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How do I answer this question?​
Novay_Z [31]

Due to the Triangle Angle Sum Theorem, we know that the sum of the interior angles of a triangle equals 180 degrees, therefore,

180 = m<1 + m<2 + m<3

180 - m<3 = m<1 + m<2

But, we also know that m<4 + m<3 = 180 degrees.

180 = m<3 + m<4

180 - m<3 = m<4

Both m<4 and m<1 + m<2  equals 180 - m<3

m<4 = m<1 + m<2

5 0
3 years ago
Juan rides his bike 30 miles in 8 hours. At this rate how many miles does he ride his bike
irinina [24]

Answer:

answer is 7.5 miles

Step-by-step explanation:

30/8=3.75 mi in one hour

3.75*2=7.5 miles in 2 hours

hope it helps

6 0
3 years ago
The sum of two numbers is 40, and their difference is 8. Find the numbers.
Fudgin [204]
x+y=40\\&#10;x-y=8\\&#10;-----\\&#10;2x=48\\&#10;x=24\\\\&#10;24+y=40\\&#10;y=16
3 0
3 years ago
Read 2 more answers
Five boxes of crackers cost $9.at this rate how much do 20 boxes cost
just olya [345]

Find how much 1 box costs by dividing.

9 ÷ 5 = 1.80

Now, multiply 1.80 by 20.

1.80 × 20 = 36

<h2>Answer:</h2>

<u>20 boxes of cookies costs </u><u>$36</u><u>.</u>

5 0
3 years ago
Read 2 more answers
Solve y=f(x) for x. Then find the input when the output is -3.
DochEvi [55]

Answer:

Please check the explanation

Step-by-step explanation:

Given the function

f\left(x\right)\:=\:\left(x-5\right)^3-1

Given that the output = -3

i.e. y = -3

now substituting the value y=-3 and solve for x to determine the input 'x'

\:\:y=\:\left(x-5\right)^3-1

-3\:=\:\left(x-5\right)^3-1\:\:\:

switch sides

\left(x-5\right)^3-1=-3

Add 1 to both sides

\left(x-5\right)^3-1+1=-3+1

\left(x-5\right)^3=-2

\mathrm{For\:}g^3\left(x\right)=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}

Thus, the input values are:

x=-\sqrt[3]{2}+5,\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}-i\frac{\sqrt[3]{2}\sqrt{3}}{2},\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}+i\frac{\sqrt[3]{2}\sqrt{3}}{2}

And the real input is:

x=-\sqrt[3]{2}+5

  • x=3.74
4 0
3 years ago
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