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alisha [4.7K]
3 years ago
7

Linda sells her bracket for $6 And her necklace for $10 what is the expression or equation

Mathematics
1 answer:
rosijanka [135]3 years ago
4 0

The equation is 6x+10y

Step-by-step explanation:

The bracket is denoted by the variable x.

The necklace is denoted by the variable y.

From given, Linda sells her bracket for $6.

Thus, the expression for bracket is 6x.

Also, Linda sells her necklace for $10.

Thus, the expression for necklace is 10y.

The equation for Linda sells her bracket and necklace is 6x+10y

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50% of 70 <br> help! I don’t understand!!
Tcecarenko [31]

Answer:

The answer is 35.

Step-by-step explanation:

50% means half of a number.

For example, 50% of 20 is 10, because half of 20 is 10.

In this situation, the number is 70.

Do 70 divided by 2.

The answer is 35.

3 0
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Jeffersonville Bank is offering it's customers a record 3.4% compound interest on new savings accounts. Mr. Kirks opens an accou
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Brennan took a total of 16 pages of notes during 8 hours of class. After attending 10 hours of class, how many total pages of no
Nezavi [6.7K]
We use unitary method over here. To find out the number pages he writes in 1 hour we should;
16÷8 = 2.
So Brennan writes 2 pages in 1 hour.
Hence, in 10 hours he writes;
2 × 10 = 20.
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6 0
3 years ago
Given: AB = 12
Alexxx [7]

In proving  that C is the midpoint of AB, we see truly that C has Symmetric  property.

<h3>What is the proof about?</h3>

Note that:

AB = 12

AC = 6.

BC = AB - AC

= 12 - 6

=6

So, AC, BC= 6

Since C is in the middle, one can say that C is the midpoint of AB.

Note that the use of segment addition property shows: AC + CB = AB = 12

Since it has Symmetric property, AC = 6 and Subtraction property shows that CB = 6

Therefore,  AC = CB and thus In proving  that C is the midpoint of AB, we see truly that C has Symmetric  property.

See full question below

Given: AB = 12 AC = 6 Prove: C is the midpoint of AB. A line has points A, C, B. Proof: We are given that AB = 12 and AC = 6. Applying the segment addition property, we get AC + CB = AB. Applying the substitution property, we get 6 + CB = 12. The subtraction property can be used to find CB = 6. The symmetric property shows that 6 = AC. Since CB = 6 and 6 = AC, AC = CB by the property. So, AC ≅ CB by the definition of congruent segments. Finally, C is the midpoint of AB because it divides AB into two congruent segments. Answer choices: Congruence Symmetric Reflexive Transitive

Learn more about midpoint from

brainly.com/question/6364992

#SPJ1

3 0
2 years ago
The box and whisker plots below show two classes' semester grades. Write a paragraph comparing the two sets of
oksano4ka [1.4K]

The paragraph to show the comparision between two classes semester grades on the basis of the terms

  • extremes
  • quartiles
  • medians
  • ranges

is given below:

<h3>What is Box and Whisker plots?</h3>

A box and whisker plot is defined as a graphical method of displaying variation in a set of data.

From the first figure, write all the values where dark point is drawn

53, 62, 80, 86, 89  

  • The lower extreme is the smallest value, which is 53.

        The upper extreme is the highest value, which is 89.

  • The median will be the middle of data , which is 80

  • The upper quartile is the median of the upper region and the lower quartile is the median of the lower region.

        The upper quartile is 86 and the lower quartile is 62.

  • Range of the data be,

       = Highest - Lowest

       =89-53

       =36

From the second figure, write all the values where dark point is drawn

56, 62, 74, 89, 96

  • The lower extreme is the smallest value, which is 56.

        The upper extreme is the highest value, which is 96.

  • The median will be the middle of data , which is 74.

  • The upper quartile is the median of the upper region and the lower quartile is the median of the lower region.

       The upper quartile is 89 and the lower quartile is 62.

  • Range of the data be,

       = Highest - Lowest

       =96-62

       =34

From the above discussion,  

  • The First class have less upper extreme value than the second class.
  • The First class have less lower extreme value than the second class.
  • The First class have greater median than the second class.
  • The First class have less upper quartile than the second class.
  • The First and second class have equal lower quartile.
  • The First class have greater range than the second class.

The comparision of the two classes on the basis of extremes, quartile, median, range is concluded above.

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6 0
2 years ago
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